如何让一个线程不冻结整个JFrame。 JAVA [英] How to make a thread not freeze you whole JFrame. JAVA

问题描述

嘿，我只需要回答一个问题...
如何让以下代码不冻结我的整个JFrame？

  try {
 Thread.sleep（Integer.parseInt（delayField.getText（））* 1000）; 
 System.out.println（你好！）; 
} catch（InterruptedException ex）{
 Thread.currentThread（）。interrupt（）; 
} 
  

解决方案

使用不同的线程执行这个任务。如果你在主UI线程中执行此操作，那么它将冻结..例如，您可以执行以下操作

  new Thread（）{ 
 
 @Override 
 public void run（）{
 try {
 Thread.sleep（Integer.parseInt（delayField.getText（））* 1000）; 
 System.out.println（你好！）; 
} catch（InterruptedException ex）{
 Thread.currentThread（）。interrupt（）; 
} 
 
} 
} .start（）; 
  

更新

<罗宾和马可的明智建议我正在用更好的解决方案更新答案。

  ActionListener taskPerformer = new ActionListener（）{
 public void actionPerformed（ActionEvent evt）{
 System。通过out.println（ 你好！）; 
 
} 
}; 
 javax.swing.Timer t = new javax.swing.Timer（Integer.parseInt（delayField.getText（））* 1000，taskPerformer）; 
 t.setRepeats（false）; 
 t.start（）; 
  

Hey i just need a question answered... How would i make the following code not freeze my whole JFrame?

                try {
                Thread.sleep(Integer.parseInt(delayField.getText()) * 1000);
                System.out.println("Hello!");
            } catch(InterruptedException ex) {
                Thread.currentThread().interrupt();
            }

解决方案

use a different thread to perform this task. If you do this in the main UI thread then it will freeze.. For example you can do following

  new Thread() {

        @Override
        public void run() {
            try {
                Thread.sleep(Integer.parseInt(delayField.getText()) * 1000);
                System.out.println("Hello!");
            } catch (InterruptedException ex) {
                Thread.currentThread().interrupt();
            }

        }
    }.start();

UPDATE

AFter wise suggestions of Robin and Marko I am updating the answer with a better solution.

    ActionListener taskPerformer = new ActionListener() {
        public void actionPerformed(ActionEvent evt) {
                System.out.println("Hello!");

        }
    };
    javax.swing.Timer t = new javax.swing.Timer(Integer.parseInt(delayField.getText()) * 1000, taskPerformer);
    t.setRepeats(false);
    t.start();

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