是否可以在Java 8中强制转换流? [英] Is it possible to cast a Stream in Java 8?
问题描述
是否可以在Java 8中强制转换流?假设我有一个对象列表,我可以做这样的事情来过滤掉所有其他对象:
Is it possible to cast a stream in Java 8? Say I have a list of objects, I can do something like this to filter out all the additional objects:
Stream.of(objects).filter(c -> c instanceof Client)
在此之后,如果我想要我需要为客户做一些事情:
After this though, if I want to do something with the clients I would need to cast each of them:
Stream.of(objects).filter(c -> c instanceof Client)
.map(c -> ((Client) c).getID()).forEach(System.out::println);
这看起来有点难看。是否可以将整个流转换为其他类型?喜欢将 Stream< Object>
投射到 Stream< Client>
?
This looks a little ugly. Is it possible to cast an entire stream to a different type? Like cast Stream<Object>
to a Stream<Client>
?
请忽略这样的事实,即做这样的事情可能意味着糟糕的设计。我在计算机科学课上做了这样的事情,所以我正在研究java 8的新功能,如果可能的话,我很好奇。
Please ignore the fact that doing things like this would probably mean bad design. We do stuff like this in my computer science class, so I was looking into the new features of java 8 and was curious if this was possible.
推荐答案
我认为没有办法做到开箱即用。一个可能更清晰的解决方案是:
I don't think there is a way to do that out-of-the-box. A possibly cleaner solution would be:
Stream.of(objects)
.filter(c -> c instanceof Client)
.map(c -> (Client) c)
.map(Client::getID)
.forEach(System.out::println);
或者,如评论中所建议的那样,你可以使用 cast
方法 - 前者可能更容易阅读:
or, as suggested in the comments, you could use the cast
method - the former may be easier to read though:
Stream.of(objects)
.filter(Client.class::isInstance)
.map(Client.class::cast)
.map(Client::getID)
.forEach(System.out::println);
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