如何从Java过滤器获取请求URL? [英] How can I get the request URL from a Java Filter?
本文介绍了如何从Java过滤器获取请求URL?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试编写一个可以检索请求网址的过滤器,但我不知道该怎么做。
I am trying to write a filter that can retrieve the request URL, but I'm not sure how to do so.
这是我到目前为止所拥有的:
Here is what I have so far:
import javax.servlet.*;
import javax.servlet.http.HttpServletRequest;
import java.io.IOException;
public class MyFilter implements Filter {
public void init(FilterConfig config) throws ServletException { }
public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws ServletException, IOException {
chain.doFilter(request, response);
String url = ((HttpServletRequest) request).getPathTranslated();
System.out.println("Url: " + url);
}
public void destroy() { }
}
当我点击服务器上的某个页面时,我看到的唯一输出是Url:null。
When I hit a page on my server, the only output I see is "Url: null".
获取请求的URL的正确方法是什么来自Filter中给定的ServletRequest对象?
What is the correct way to get the requested URL from a given ServletRequest object in a Filter?
推荐答案
这是您要找的吗?
if (request instanceof HttpServletRequest) {
String url = ((HttpServletRequest)request).getRequestURL().toString();
String queryString = ((HttpServletRequest)request).getQueryString();
}
重建:
System.out.println(url + "?" + queryString);
HttpServletRequest.getRequestURL()
和 HttpServletRequest.getQueryString( )
。
这篇关于如何从Java过滤器获取请求URL?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文