JPA Criteria构建器IN子句查询 [英] JPA Criteria builder IN clause query

问题描述

如何为下面给出的JPQL查询编写条件构建器api查询？
我正在使用 JPA 2.2 。

How to write criteria builder api query for below given JPQL query? I am using JPA 2.2.

SELECT * 
FROM Employee e
WHERE e.Parent IN ('John','Raj')
ORDER BY e.Parent

推荐答案

这个标准设置应该可以解决问题：

This criteria set-up should do the trick:

CriteriaBuilder cb = entityManager.getCriteriaBuilder();
CriteriaQuery<Employee> q = cb.createQuery(Employee.class);


Root<Employee> root = q.from(Employee.class);
q.select(root);

List<String> parentList = Arrays.asList(new String[]{"John", "Raj"});

Expression<String> parentExpression = root.get(Employee_.Parent);
Predicate parentPredicate = parentExpression.in(parentList);
q.where(parentPredicate);
q.orderBy(cb.asc(root.get(Employee_.Parent));

q.getResultList();

我在这里使用了重载的 CriteriaQuery.where 方法，该方法接受 Predicate .. in 谓词。

I have used the overloaded CriteriaQuery.where method here which accepts a Predicate.. an in predicate in this case.

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