如何用Java创建ZIP文件？ [英] How do I create a ZIP file in Java?

问题描述

这个jar命令的Java等价物是什么：

What is the Java equivalent to this jar command:

C:\>jar cvf myjar.jar directory

我想以编程方式创建这个jar文件，因为我不能确定 jar 命令将位于我可以运行外部进程的系统路径上。

I'd like to create this jar file programmatically as I can't be assured that the jar command will be on the system path where I could just run the external process.

编辑：我想要的只是归档（和压缩）一个目录。不必遵循任何java标准。即：标准拉链是好的。

Edit: All I want is to archive (and compress) a directory. Doesn't have to follow any java standard. Ie: a standard zip is fine.

推荐答案

// These are the files to include in the ZIP file
    String[] source = new String[]{"source1", "source2"};

    // Create a buffer for reading the files
    byte[] buf = new byte[1024];

    try {
        // Create the ZIP file
        String target = "target.zip";
        ZipOutputStream out = new ZipOutputStream(new FileOutputStream(target));

        // Compress the files
        for (int i=0; i<source.length; i++) {
            FileInputStream in = new FileInputStream(source[i]);

            // Add ZIP entry to output stream.
            out.putNextEntry(new ZipEntry(source[i]));

            // Transfer bytes from the file to the ZIP file
            int len;
            while ((len = in.read(buf)) > 0) {
                out.write(buf, 0, len);
            }

            // Complete the entry
            out.closeEntry();
            in.close();
        }

        // Complete the ZIP file
        out.close();
    } catch (IOException e) {
    }

你也可以使用从这篇文章中回答如何使用JarOutputStream创建JAR文件？

You can also use the answer from this post How to use JarOutputStream to create a JAR file?

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