在java中强制转换的优先级是什么？ [英] What is the priority of casting in java?

问题描述

如果我有一行代码类似

int s = (double) t/2   

是否与

int s = (double) (t/2)

或

int s = ((double) t)/2

？

推荐答案

这应该会让事情变得更加清晰。简单地说，一个演员优先于一个除法运算，所以它与是相同的。给出相同的输出

This should make things a bit clearer. Simply put, a cast takes precedence over a division operation, so it would be the same thing as give the same output as

int s = ((double)t) / 2;

编辑：正如knoight指出的那样，这在技术上并不相同没有括号的操作，因为它们也有优先权。但是，出于本示例的目的，它将提供相同的结果，并且用于所有意图和目的。

As knoight has pointed out, this is not technically the same operation as it would be without the parentheses, since they have a priority as well. However, for the purposes of this example, it will offer the same result, and is for all intents and purposes equivalent.

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