具有CONTAINS功能的JPA Criteria api [英] JPA Criteria api with CONTAINS function
本文介绍了具有CONTAINS功能的JPA Criteria api的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试使用CONTAINS函数(MS SQL)创建Criteria API查询:
I'm trying to crete Criteria API query with CONTAINS function(MS SQL):
select * from com.t_person where where(last_name,'xxx')
select * from com.t_person where contains(last_name,'xxx')
CriteriaBuilder cb = em.getCriteriaBuilder();
CriteriaQuery<Person> cq = cb.createQuery(Person.class);
Root<Person> root = cq.from(Person.class);
Expression<Boolean> function = cb.function("CONTAINS", Boolean.class,
root.<String>get("lastName"),cb.parameter(String.class, "containsCondition"));
cq.where(function);
TypedQuery<Person> query = em.createQuery(cq);
query.setParameter("containsCondition", lastName);
return query.getResultList();
但是获得异常:
org.hibernate.hql.internal.ast.QuerySyntaxException:unexpected AST节点:
But getting exception: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected AST node:
任何帮助?
推荐答案
如果你想要坚持使用 CONTAINS
,它应该是这样的:
If you want to stick with using CONTAINS
, it should be something like this:
//Get criteria builder
CriteriaBuilder cb = em.getCriteriaBuilder();
//Create the CriteriaQuery for Person object
CriteriaQuery<Person> query = cb.createQuery(Person.class);
//From clause
Root<Person> personRoot = query.from(Person.class);
//Where clause
query.where(
cb.function(
"CONTAINS", Boolean.class,
//assuming 'lastName' is the property on the Person Java object that is mapped to the last_name column on the Person table.
personRoot.<String>get("lastName"),
//Add a named parameter called containsCondition
cb.parameter(String.class, "containsCondition")));
TypedQuery<Person> tq = em.createQuery(query);
tq.setParameter("containsCondition", "%näh%");
List<Person> people = tq.getResultList();
您的问题似乎缺少一些代码,所以我在做一些假设这个片段。
It seems like some of your code is missing from your question so I'm making a few assumptions in this snippet.
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