如何使用JAXB从服务返回的'anyType'创建java对象？ [英] How to create java object from 'anyType' returned from service using JAXB?

问题描述

Web服务返回由WSDL定义的对象：

A web service is returning an object defined by the WSDL to be:

<s:complexType mixed="true"><s:sequence><s:any/></s:sequence></s:complexType>

当我打印出这个对象的课程信息时，它会显示为：

When I print out this object's class info, it comes up as:

class com.sun.org.apache.xerces.internal.dom.ElementNSImpl

但我需要将此对象解组为以下类的对象：

But I need to unmarshall this object as an object of the following class:

@XmlAccessorType(XmlAccessType.FIELD) 
@XmlType(name = "", propOrder = {
        "info",
        "availability",
        "rateDetails",
        "reservation",
        "cancellation",
        "error" }) 
@XmlRootElement(name = "ArnResponse") 
public class ArnResponse { }

我知道答案是正确的，因为我知道如何编组这个对象的XML：

I know the response is correct, since I know how to marshall this object's XML:

Marshaller m = jc.createMarshaller();
m.setProperty( Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE );
m.marshal(rootResponse, System.out);

打印出来：

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<ns2:SubmitRequestDocResponse xmlns:ns2="http://tripauthority.com/hotel">
    <ns2:SubmitRequestDocResult>
        <!-- below is the object I'm trying to unmarshall -->
        <ArnResponse>
            <Info />
            <Availability>
                <!-- etc--> 
             </Availability>
        </ArnResponse>
    </ns2:SubmitRequestDocResult>
</ns2:SubmitRequestDocResponse>

如何转动 ElementNSImpl 对象I我看到 ArnResponse 对象我知道它代表什么？

How can I turn the ElementNSImpl object I'm seeing into the ArnResponse object I know it represents?

此外，我正在AppEngine上运行，其中文件访问受到限制。

Additionally, I'm running on AppEngine, where file access is restricted.

感谢您的帮助

更新：

我添加了 @XmlAnyElement（lax = true）注释，如下所示：

I've added the @XmlAnyElement(lax=true) annotation, like so:

  @XmlAccessorType(XmlAccessType.FIELD)
  @XmlType(name = "", propOrder = {
      "content"
  })
  @XmlSeeAlso(ArnResponse.class)
  public static class SubmitRequestDocResult {

    @XmlMixed
    @XmlAnyElement(lax = true)
    protected List<Object> content;

但它没有任何区别。

这是否与内容为列表的事实有关？

Is this something to do with the fact that the content is a List?

以下是我从服务器取回内容后尝试访问内容的代码：

Here's the code where I'm trying to access the content after getting it back from the server:

List list = rootResponse.getSubmitRequestDocResult().getContent();

for (Object o : list) {
  ArnResponse response = (ArnResponse) o;
  System.out.println(response);
}

哪个有输出：

2012年1月31日上午10:04:14
com.districthp.core.server.ws.alliance.AllianceApi getRates严重：
com.sun.org .apache.xerces.internal.dom.ElementNSImpl无法强制转换为
com.districthp.core.server.ws.alliance.response.ArnResponse

Jan 31, 2012 10:04:14 AM com.districthp.core.server.ws.alliance.AllianceApi getRates SEVERE: com.sun.org.apache.xerces.internal.dom.ElementNSImpl cannot be cast to com.districthp.core.server.ws.alliance.response.ArnResponse

答案：

axtavt的答案就行了。这工作：

axtavt's answer did the trick. This worked:

Object content = ((List)result.getContent()).get(0);
JAXBContext context = JAXBContext.newInstance(ArnResponse.class);
Unmarshaller um = context.createUnmarshaller();
ArnResponse response = (ArnResponse)um.unmarshal((Node)content);
System.out.println("response: " + response);

推荐答案

您可以将该对象传递给 Unmarshaller.unmarshal（节点），它应该能够解组它。

You can pass that object to Unmarshaller.unmarshal(Node), it should be able to unmarshal it.

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