生成颜色渐变的C# [英] Generate Color Gradient in C#

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本文介绍了生成颜色渐变的C#的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

在这里我的问题是类似这里问题,但我使用C#的工作。

My question here is similar to the question here, except that I am working with C#.

我有两个颜色,我有一个predefine步骤。如何检索颜色 s表示两者之间的渐变列表?

I have two colors, and I have a predefine steps. How to retrieve a list of Colors that are the gradients between the two?

这是我试过了,没有工作的方法:

This is an approach that I tried, which didn't work:

int argbMax = Color.Chocolate.ToArgb();
int argbMin = Color.Blue.ToArgb();
var colorList = new List<Color>();

for(int i=0; i<size; i++)
{
    var colorAverage= argbMin + (int)((argbMax - argbMin) *i/size);
    colorList.Add(Color.FromArgb(colorAverage));
}

如果您尝试了上面code,你会发现,在的argb 逐渐增加不对应的颜色视觉逐渐增加。

If you try the above code, you will find that a gradual increase in argb doesn't correspond to a visual gradual increase in the color.

在这个任何想法?

推荐答案

您必须提取R,G,B分量并分别对他们每个人执行相同的线性插值,然后重新组合。

You will have to extract the R, G, B components and perform the same linear interpolation on each of them individually, then recombine.

int rMax = Color.Chocolate.R;
int rMin = Color.Blue.R;
// ... and for B, G
var colorList = new List<Color>();
for(int i=0; i<size; i++)
{
    var rAverage = rMin + (int)((rMax - rMin) * i / size);
    // ... and for B, G
    colorList.Add(Color.FromArgb(rAverage, gAverage, bAverage));
}

这篇关于生成颜色渐变的C#的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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