将Serializable对象传递给Pending Intent [英] Pass Serializable Object to Pending Intent
本文介绍了将Serializable对象传递给Pending Intent的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试将一个可序列化的对象发送到待处理的Intent。问题是收到的警报返回为null。即使Alarm实现了可序列化的接口。
I am trying to send a serializable object to a pending Intent. The problem is the alarm being received is returning as null. Even though the Alarm implements the serializable interface.
//AlarmService.java
Intent myIntent = new Intent(getApplicationContext(), AlarmAlertBroadcastReciever.class);
Bundle bundle = new Bundle();
bundle.putSerializable("alarm", alarm);
myIntent.putExtras(bundle);
PendingIntent pendingIntent = PendingIntent.getBroadcast(getApplicationContext(), 0, myIntent, PendingIntent.FLAG_CANCEL_CURRENT);
AlarmManager alarmManager = (AlarmManager)getApplicationContext().getSystemService(Context.ALARM_SERVICE);
alarmManager.set(AlarmManager.RTC_WAKEUP, alarm.getAlarmTime().getTimeInMillis(), pendingIntent);
收到的警报为空。
//AlarmAlertBroadcastReceiver.java
public class AlarmAlertBroadcastReciever extends BroadcastReceiver {
@Override
public void onReceive(Context context, Intent intent) {
Alarm alarm = (Alarm)intent.getExtras().getSerializable("alarm");
}
}
编辑:
我尝试过的更多内容如下,但它似乎不起作用:
Some more things I've tried is as follows, but it doesn't seem to work:
//AlarmService.java
Intent myIntent = new Intent(getApplicationContext(), AlarmAlertBroadcastReciever.class);
myIntent.putExtra("alarm", alarm);
myIntent.setAction("abc.xyz");
PendingIntent pendingIntent = PendingIntent.getBroadcast(getApplicationContext(), 0, myIntent, PendingIntent.FLAG_UPDATE_CURRENT);
AlarmManager alarmManager = (AlarmManager)getApplicationContext().getSystemService(Context.ALARM_SERVICE);
alarmManager.set(AlarmManager.RTC_WAKEUP, alarm.getAlarmTime().getTimeInMillis(), pendingIntent);
收到的警报为空。
//AlarmAlertBroadcastReceiver.java
public class AlarmAlertBroadcastReciever extends BroadcastReceiver {
@Override
public void onReceive(Context context, Intent intent) {
Alarm alarm = (Alarm)intent.getExtras().getSerializable("alarm");
//Alarm alarm = (Alarm)intent.getSerializableExtra("alarm");
}
}
推荐答案
我我正在使用android Nougat所以这些答案都没有完全奏效。我最终以字节数组传递对象。
I am using android Nougat so none of these answers quite worked. I ended up passing the objects in a byte array.
//AlarmService.java
Intent myIntent = new Intent(getApplicationContext(), AlarmAlertBroadcastReciever.class);
ByteArrayOutputStream bos = new ByteArrayOutputStream();
ObjectOutputStream out = null;
try {
out = new ObjectOutputStream(bos);
out.writeObject(alarm);
out.flush();
byte[] data = bos.toByteArray();
myIntent.putExtra("alarm", data);
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
bos.close();
} catch (IOException ex) {
ex.printStackTrace();
}
}
PendingIntent pendingIntent = PendingIntent.getBroadcast(getApplicationContext(), 0, myIntent, PendingIntent.FLAG_CANCEL_CURRENT);
AlarmManager alarmManager = (AlarmManager) getApplicationContext().getSystemService(Context.ALARM_SERVICE);
alarmManager.set(AlarmManager.RTC_WAKEUP, alarm.getAlarmTime().getTimeInMillis(), pendingIntent);
然后我收到了Byte []
Then I received the Byte[]
//AlarmAlertBroadcastReceiver.java
@Override
public void onReceive(Context context, Intent intent) {
ByteArrayInputStream bis = new ByteArrayInputStream(intent.getByteArrayExtra("alarm"));
ObjectInput in = null;
Alarm alarm = null;
try {
in = new ObjectInputStream(bis);
alarm = (Alarm)in.readObject();
} catch (ClassNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
if (in != null) {
in.close();
}
} catch (IOException ex) {
ex.printStackTrace();
}
}
}
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