如何检查文件是否可读？ [英] How to check if a file is readable?

问题描述

我正在编写Java 6应用程序，我必须检查文件是否可读。但是，在Windows上 canRead（）始终返回 true 。所以我看到可能，唯一的解决方案可能是基于WINAPI并用JNA / JNI编写的一些原生解决方案。

I'm writing Java 6 application and I have to check if a file is readable. However, on Windows canRead() always returns true. So I see that probably, the only solution could be some native solution based on WINAPI and written in JNA/JNI.

但是，还有另一个问题，因为在WINAPI中很难找到一个简单的函数，它会返回有关文件访问的信息。我发现 GetNamedSecurityInfo 或 GetSecurityInfo 但我不是一个高级的WINAPI程序员，它们对我来说太复杂了JNA / JNI。有什么想法如何处理这个问题？

But, there is another problem, because it's difficult to find a simple function in WINAPI which would return information about access to a file. I found GetNamedSecurityInfo or GetSecurityInfo but I'm not an advanced WINAPI programmer and they are too complicated for me in connection with JNA/JNI. Any ideas how to deal with this problem?

推荐答案

尝试使用以下代码

public boolean checkFileCanRead(File file){
    try {
        FileReader fileReader = new FileReader(file.getAbsolutePath());
        fileReader.read();
        fileReader.close();
    } catch (Exception e) {
        LOGGER.debug("Exception when checking if file could be read with message:"+e.getMessage(), e);
        return false;
    }
    return true;
}

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