java支持if-then-else regexp构造(Perl构造)吗? [英] does java support if-then-else regexp constructs(Perl constructs)?

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问题描述

我在尝试编译以下正则表达式时收到PatternSyntaxException:

I receive PatternSyntaxException when try to compile the following regex:

"bd".matches("(a)?b(?(1)c|d)")

这个正则表达式匹配bd和abc。它与bc不匹配。

this regex matches bd and abc. It does not match bc.

任何想法?谢谢。

好的我需要写正则表达式以匹配接下来的4个字符串:

ok i need to write regex to match next 4 strings:

*date date* date date1*date2

不匹配:

*date* date1*date2* *date1*date2 date** ...

但这应该通过单个匹配来完成,而不是几个。

but this should be done with single matching, not several.

请不要发布以下答案:

(date*date)|(*date)|(date*)|(date)


推荐答案

根据OP的编辑和样本添加新答案:

Adding a new answer based on the OP's edit and samples:

确定我需要编写正则表达式来匹配接下来的4个字符串:

*日期日期*日期date1 * date2

不匹配:

* date * date1 * date2 * * date1 * date2 date ** ...

如果我认为我理解你,你可以使用基于的正则表达式Alan Moore伪条件技巧。

If I think I understand you, you could use a regex based on Alan Moore pseudo conditional trick.

像这样的东西 ^(?:[*]()) ?日期(?:(?!\ 1)[*](?:日期)?|)$ 可能会有效。

我认为'日期'是唯一的样本中的文本,样本中的每组非空格字符都是不同的文本行。

Something like this ^(?:[*]())?date(?:(?!\1)[*](?:date)?|)$ might work.
I am asuming 'date' is the only text in the samples, and each group of non-space characters in the samples are distinct lines of text.

在通过的文本中,只有一个表单需要伪条件。那是'日期*日期'。所以,我在下面包含了一个Perl示例(因为我没有Java编译器),为了清晰起见扩展了正则表达式。

In your text that passes, there is only one form that requires a pseudo conditional. That is 'date*date'. So, I've included a Perl sample below (since I don't have a Java compiler) that expands the regex for clarity.

use strict;
use warnings;

my @samps = qw(

*date
 date*
 date
 date*date
*date*
 date*date*
*date*date
 date**
);

for my $str (@samps)
{
   print "\n'$str'\n";

   if ($str =~
       /
        ^          # Begin of string
        (?:             # Expr grouping
            [*]()          # Asterisk found then DEFINE capture group 1 as empty string
        )?              # End expr group, optional, if asterisk NOT found, capture group 1 stays UNDEFined
        date   #  'data'
        (?:             # Expr grouping
            (?!\1)           # Pseudo conditional: If no asterisk (group 1 is UNDEF), then
            [*](?:date)?     # look for '*' folowed by optional 'data'
          |               # OR,
        )                    # Asterisk or not, should be nothing here
        $          # End of string
      /x)

     {
         print "matched: '$str'\n";
     }
}

输出:

'*date'
matched: '*date'

'date*'
matched: 'date*'

'date'
matched: 'date'

'date*date'
matched: 'date*date'

'*date*'

'date*date*'

'*date*date'

'date**'

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