Java：对String数组进行排序，其字符串表示int [英] Java: sort a String array, whose strings represent int

问题描述

我有 String [] 数组如

{"3","2","4","10","11","6","5","8","9","7"}

我想按数字顺序对其进行排序，而不是按字母顺序排序。

I want to sort it in numerical order, not in alphabetical order.

如果我使用

Arrays.sort(myarray);

我获得

{"10","11","2","3","4","5","6","7","8","9"}

而不是

{"2","3","4","5","6","7","8","9","10","11"}

推荐答案

我认为到目前为止转换字符串 s到 int s：

I think by far the easiest and most efficient way it to convert the Strings to ints:

int[] myIntArray = new int[myarray.length];

for (int i = 0; i < myarray.length; i++) {
    myIntArray[i] = Integer.parseInt(myarray[i]);
}

然后对整数数组进行排序。如果你真的需要，你可以随后转换回来：

And then sort the integer array. If you really need to, you can always convert back afterwards:

for (int i = 0; i < myIntArray.length; i++) {
    myarray[i] = "" + myIntArray[i];
}

另一种方法是使用比较器界面，用于确切地说明元素的比较方式，但这可能相当于无论如何将每个 String 值转换为 int - 使上述方法更有效。

An alternative method would be to use the Comparator interface to dictate exactly how elements are compared, but that would probably amount to converting each String value to an int anyway - making the above approach much more efficient.

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