如何在Java中以0.1f的增量在0.1f和1.0f之间进行迭代？ [英] How to iterate between 0.1f and 1.0f with 0.1f increments in Java?

问题描述

可能重复：

Java浮动和双打，如何避免0.0 + 0.1 + ... + 0.1 == 0.9000001？

我在Java中遇到以下问题 - 我需要在0.1f和1.0之间迭代f以0.1f为增量，所以我希望我的输出看起来像这样：

I am having a following problem in Java - I need to iterate between 0.1f and 1.0f in 0.1f increments,so I would like my output to look like this:

    0.1
    0.2
    0.3
    0.4
    ...
    0.9

相反，当我这样做时：

for(float i = 0.1f; i < 1f; i += 0.1f)
    System.out.println(i);

我得到

0.1
0.2
0.3
0.4
0.5
0.6
0.70000005
0.8000001
0.9000001

我想它与计算机表示分数的方式有关，但我想知道为什么是这个，如果我有什么办法可以阻止它。
谢谢。

I imagine it has something to do with the way fractions are represented by a computer,but I would like to know why is this,and if there is anything I can do to stop it. thanks.

推荐答案

在for循环中使用整数以避免重复的浮点数学运算，这会导致浮点错误。

Use integers in your for loop to avoid repeated floating point math, which compounds floating-point errors.

for (int i = 1; i < 10; i++)
{
   float f = (float) i / 10.0f;
   System.err.println(f);
}

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