Java字符串中的不可见字符 [英] Invisible characters in Java Strings

问题描述

String a = "Hello\u200e";
String b = "Hello\u200f";

System.out.println("a = '" + a + "' and b = '" + b + "' are length "
                     + a.length() + " and " + b.length()
                     + ", equals() is " + a.equals(b));

上面代码段中的代码产生以下输出。

The code in the above code snippet produces the following output.

a ='Hello'和b ='Hello'的长度为6和6，equals（）为false

a = 'Hello‎' and b = 'Hello‏' are length 6 and 6, equals() is false

虽然控制台上显示的 a 和 b 的值均为 Hello ， a.equals（b）返回 false 。怎么样？

Although the value of both a and b displayed on the console is Hello‏, a.equals(b) returns false. How?

推荐答案

U + 200E 和 U + 200F 不可打印字符。它们都是控制字符，用于指示文本应该如何呈现 - 从左到右，或从右到左。

U+200E and U+200F are not printable characters. They're both control characters which dictate how the text should be rendered - either left to right, or right to left.

你不会在终端中看到这些，它们不应该是等价的字符串。

You won't see these in the terminal, and they shouldn't be equivalent strings.

^{0x200E ^ 0x200F！= 0}

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