JAXB是否支持默认架构值？ [英] Does JAXB support default schema values?

问题描述

我有一个模式，用于定义元素和属性的默认值。我试图使用基于该模式的JAXB解析文档，但JAXB没有设置默认值。关于如何使JAXB尊重模式中的默认值的任何想法？

I have a schema that defines default values for elements and attributes. I am trying to parse a document using JAXB based on that schema but JAXB is not setting the default values. Any ideas on how to make JAXB honor the default values from the schema?

example.xsd：

example.xsd:

<?xml version="1.0" encoding="UTF-8"?><xs:schemaxmlns:xs="http://www.w3.org/2001/XMLSchema" 
targetNamespace="http://www.example.org/example" 
xmlns:tns="http://www.example.org/example">

<xs:element name="root" type="tns:rootType"/>

<xs:complexType name="rootType">
    <xs:sequence>
        <xs:element name="child" type="tns:childType"/>
    </xs:sequence>
</xs:complexType>

<xs:complexType name="childType">
    <xs:sequence>
        <xs:element name="childVal" type="xs:string" default="defaultElVal"/>
    </xs:sequence>
    <xs:attribute name="attr" type="xs:string" default="defaultAttrVal"/>
</xs:complexType>

example1.xml

example1.xml

<?xml version="1.0" encoding="UTF-8"?>
<tns:root xmlns:tns="http://www.example.org/example" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.example.org/example example.xsd ">
  <child>
    <childVal/>
  </child>
</tns:root>

TestParser.java

TestParser.java

package test;  
import java.io.File;  
import javax.xml.XMLConstants;  
import javax.xml.bind.JAXBContext;  
import javax.xml.bind.Unmarshaller;  
import javax.xml.validation.Schema;  
import javax.xml.validation.SchemaFactory;  
public class TestParser {    
    public static void main(String[] pArgs) {  
        try {  
            JAXBContext context = JAXBContext.newInstance(RootElement.class);  
            Unmarshaller unmarshaller = context.createUnmarshaller();  

            SchemaFactory schemaFac = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
            Schema sysConfigSchema = schemaFac.newSchema(
                    new File("example.xsd"));
            unmarshaller.setSchema(sysConfigSchema);
            RootElement root = (RootElement)unmarshaller.unmarshal(
                    new File("example1.xml"));
            System.out.println("Child Val: " + root.getChild().getChildVal());
            System.out.println("Child Attr: " + root.getChild().getAttr());
        } catch (Exception e) {
            System.out.println(e.getMessage());
            e.printStackTrace();
        }
    }
}

RootElement.java

RootElement.java

package test;  
import javax.xml.bind.annotation.XmlRootElement;  

@XmlRootElement(name="root", namespace="http://www.example.org/example")  
public class RootElement {  

    private ChildEl child;  

    public RootElement() {}  

    public ChildEl getChild() {
        return child;
   }

    public void setChild(ChildEl pChild) {
        this.child = pChild;
    }
}

ChildEl.java

ChildEl.java

package test;

import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement(name="child")
public class ChildEl {

    private String attr;
    private String childVal;

    public ChildEl() {};

    @XmlAttribute
    public String getAttr() {
        return attr;
    }
    public void setAttr(String pAttr) {
        this.attr = pAttr;
    }

    public String getChildVal() {
        return childVal;
    }
    public void setChildVal(String pVal) {
        this.childVal = pVal;
    }

}

推荐答案

元素默认值

要获取元素属性的默认值，您需要按如下方式对其进行注释：

To get the default value on the element property you need to annotate it as follows:

@XmlElement(defaultValue="defaultElVal")
public String getChildVal() {
    return childVal;
}

属性默认值

如果您使用 EclipseLink JAXB（MOXy） ）您将使用您提供的代码获取默认属性值。 JAXB的Metro实现中可能存在一个错误，导致无法正常工作。注意我领导MOXy实现。

If you use EclipseLink JAXB (MOXy) you will get the default attribute value using the code you supplied. There may be a bug in the Metro implementation of JAXB that is preventing this from working. Note I lead the MOXy implementation.

替代方法

以下代码适用于任何JAXB实现，无需对模型进行任何代码更改。您可以执行以下操作并利用SAXSource：

The following code should work with any JAXB implementation without requiring any code changes to your model. You could do the following and leverage SAXSource:

import java.io.File;  
import java.io.FileInputStream;

import javax.xml.XMLConstants;  
import javax.xml.bind.JAXBContext;  
import javax.xml.bind.Unmarshaller;  
import javax.xml.parsers.SAXParserFactory;
import javax.xml.transform.sax.SAXSource;
import javax.xml.validation.Schema;  
import javax.xml.validation.SchemaFactory;  

import org.xml.sax.InputSource;
import org.xml.sax.XMLReader;
public class TestParser {    
    public static void main(String[] pArgs) {  
        try {  
            JAXBContext context = JAXBContext.newInstance(RootElement.class);  
            Unmarshaller unmarshaller = context.createUnmarshaller();  

            SchemaFactory schemaFac = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
            Schema sysConfigSchema = schemaFac.newSchema(
                    new File("example.xsd"));

            SAXParserFactory spf = SAXParserFactory.newInstance();
            spf.setNamespaceAware(true);
            spf.setSchema(sysConfigSchema);
            XMLReader xmlReader = spf.newSAXParser().getXMLReader();
            SAXSource source = new SAXSource(xmlReader, new InputSource(new FileInputStream("example1.xml")));
            RootElement root = (RootElement)unmarshaller.unmarshal(
                    source);
            System.out.println("Child Val: " + root.getChild().getChildVal());
            System.out.println("Child Attr: " + root.getChild().getAttr());
        } catch (Exception e) {
            System.out.println(e.getMessage());
            e.printStackTrace();
        }
    }
}

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