Gnuplot和Sierpinksi Triangle [英] Gnuplot and Sierpinksi Triangle

问题描述

问题：

我有一个代码，希望能生成一个Sierpinski三角形，我想知道如何输出数据文件你读到gnuplot？我从来没有使用过gnuplot，我正试着玩它。此外，如果那是不可能的，我应该如何修改我的代码以绘制我的三角形，以便我可以看到它？

I have a code, which hopefully makes a Sierpinski triangle, and I am wondering how can I output a data file that you read into gnuplot? I have never used gnuplot and I am trying to play around with it. Also, if that is not possible, how should I modify my code in order to plot my triangle so that I can see it?

代码说明：

我正在尝试生成Sierpinski三角形从点（0,0）开始，并且有一个 0.33 概率，下一步将介于两者之间当前点和（0,2）。有一个 0.33 概率，下一步将在当前点和（1，sqrt3）之间。有一个 0.33 概率，下一步将在当前点和（0,0）之间。

I am trying to generate the Sierpinski triangle which starts at the point (0,0) and there is a 0.33 probablity that the next step will be halfway between the current point and (0,2). There is a 0.33 probability that the next step will be halfway between the current point and (1,sqrt3). There is a 0.33 probability that the next step will be halfway between the current point and (0,0).

代码：

import java.util.Random;

public class SierpinskiTriangle {
    public static void main(String[] args) {
        //int N = Integer.parseInt(args[0]); // number of points
        int N = 5000;
        double sqrt3 = Math.sqrt(3);
        double x = 0.0, y = 0.0; //plots

        //need to draw triangle boundary      

        // triangle rules
        for (int i = 0; i < N; i++) {
            double r = Math.random();
            double x0, y0;
            if (r < 1/3) {
                x0 = 0.0; y0 = 0.0;
            } else if (r < 2/3) {
                x0 = 0.0; y0 = 2.0; 
            } else {
                x0 = 1.0; y0 = sqrt3;
            }
            x = (x0 + x) / 2;
            y = (y0 + y) / 2;         
        }
    }   
}

推荐答案

首先，你的代码中有几个问题：

First of all, you have a couple of problems in your code:

• 整数除法只导致第三个选项是考虑，因为1/3 = 0和2/3 = 0.使用1./3。和2./3。相反。


• 您已经交换了最后一个选项的坐标， x0 = 1.0; y0 = sqrt3; 应为 x0 = sqrt3; y0 = 1.0; 代替。

• Integer division is leading to only the third option being considered, because 1/3 = 0 and 2/3 = 0. Use 1./3. and 2./3. instead.
• You have exchanged coordinates for the last option, x0 = 1.0; y0 = sqrt3; should be x0 = sqrt3; y0 = 1.0; instead.

将点输出到名为数据（我在循环中使用 System.out.println（+ x ++ y）; ），你可以做gnuplot中的以下内容：

Once you output the points to a file called data (I used System.out.println("" + x + " " + y); within your loop), you can do the following in gnuplot:

set size ratio -1
plot "data" u 2:1 pt 7 ps 0.3

要监控三角形如何逐点创建，您可以使用带有暂停的循环：

To monitor how the triangle gets created dot by dot you can use a loop with a pause:

set xrange [0:2]
set yrange [0:1.8]
do for [i=0:4999] {
plot "data" u 2:1 every ::::i pt 7 ps 0.3
pause 0.1
}

或者你可以创建一个包含一系列png文件的动画gif：

Or you can create an animated gif with a series of png files:

set term pngcairo
do for [i=0:4999] {
set output "".i.".png"
plot "data" u 2:1 every ::::i pt 7 ps 0.3
}

期待以上是慢。您可以跳过一些帧以使其更快。然后在gnuplot外面这样做：

Expect the above to be slow. You can skip some of the frames to make it quicker. Then do this outside gnuplot:

convert -delay 10 -loop 0 *.png animation.gif

在本例中，我使用了50个点的增量并将 -delay 更改为100：

For this example I used 50 points increments and changed -delay to 100:

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