使用Play Framework获取请求参数？ [英] Get request parameter with Play Framework?

问题描述

我正在学习游戏框架，并了解我可以将 / manager / user 等请求映射为：

I am learning play framework and understand that I can map a request such as /manager/user as:

  GET      /manage/:user    Controllers.Application.some(user:String)

我如何映射像 / play / video这样的请求？video_id = 1sh1 ？

推荐答案

你至少有两种可能性，我们称之为 approach1 和 approach2 。

You have at least two possibilities, let's call them approach1 and approach2.

1. 在第一种方法中，您可以使用某个默认值声明路径参数。 0 是一个很好的候选者，因为在它之上建立一些条件是最容易的。它也是 typesafe ，并预先验证自己。我会在开头推荐这个解决方案。


2. 第二种方法直接从请求中读取params作为 String 所以你需要将它解析为整数并另外验证是否需要。

1. In the first approach you can declare a routes param with some default value. 0 is good candidate, as it will be easiest to build some condition on top of it. Also it's typesafe, and pre-validates itself. I would recommend this solution at the beginning.
2. Second approach reads params directly from request as a String so you need to parse it to integer and additionally validate if required.

routes ：

GET     /approach1      controllers.Application.approach1(video_id: Int ?=0)
GET     /approach2      controllers.Application.approach2

操作：

public static Result approach1(int video_id) {
    if (video_id == 0) return badRequest("Wrong video ID");
    return ok("1: Display video no. " + video_id);
}

public static Result approach2() {
    int video_id = 0;

    if (form().bindFromRequest().get("video_id") != null) {
        try {
            video_id = Integer.parseInt(form().bindFromRequest().get("video_id"));
        } catch (Exception e) {
            Logger.error("int not parsed...");
        }
    }

    if (video_id == 0) return badRequest("Wrong video ID");
    return ok("2: Display video no. " + video_id);
}

PS： LOL我刚刚意识到你想要的使用字符串标识符...无论如何两种方法都类似：）

PS: LOL I just realized that you want to use String identifier... anyway both approaches will be similar :)

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