正则表达式只用一个替换两个（或多个）连续字符？ [英] regular expression to replace two (or more) consecutive characters by only one?

问题描述

在java中，可以使用哪个正则表达式替换这些，例如：
：

In java, which regular expression can be used to replace these, for example:

之前：
aaabbb
之后：
ab

before: aaabbb after: ab

之前：
14442345
之后：
142345

before: 14442345 after: 142345

谢谢！

推荐答案

在perl

s/(.)\1+/$1/g;

诀窍，我认为如果java具有perl兼容的regexp它也应该工作。

Does the trick, I assume if java has perl compatible regexps it should work too.

编辑：这就是它的含义

s {
    (.)  # match any charater ( and capture it )
    \1   # if it is followed by itself 
    +    # One or more times
}{$1}gx;  # And replace the whole things by the first captured character (with g modifier to replace all occurences)

编辑：正如其他人所指出的，Java中的语法将变为

As others have pointed out, the syntax in Java would become

original.replaceAll("(.)\\1+", "$1");

记得逃避\1

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