将ByteArray转换为UUID java [英] Convert ByteArray to UUID java

问题描述

问题是如何将ByteArray转换为GUID。

Question is How do I convert ByteArray to GUID.

之前我将guid转换为字节数组，在一些事务之后我需要从字节数组中返回guid。我怎么做。虽然不相关但从Guid到byte []的转换如下所示

Previously I converted my guid to byte array, and after some transaction I need my guid back from byte array. How do I do that. Although irrelevant but conversion from Guid to byte[] is as below

    public static byte[] getByteArrayFromGuid(String str)
    {
        UUID uuid = UUID.fromString(str);
        ByteBuffer bb = ByteBuffer.wrap(new byte[16]);
        bb.putLong(uuid.getMostSignificantBits());
        bb.putLong(uuid.getLeastSignificantBits());

        return bb.array();
    }

但如何将其转换回来？

我试过这个方法，但它没有给我返回相同的值

I tried this method but its not returning me same value

    public static String getGuidFromByteArray(byte[] bytes)
    {
        UUID uuid = UUID.nameUUIDFromBytes(bytes);
        return uuid.toString();
    }

任何帮助将不胜感激。

Any help will be appreciated.

推荐答案

方法 nameUUIDFromBytes（）将名称转换为UUID。在内部，它应用散列和一些黑魔法将任何名称（即字符串）转换为有效的UUID。

The method nameUUIDFromBytes() converts a name into a UUID. Internally, it applied hashing and some black magic to turn any name (i.e. a string) into a valid UUID.

您必须使用新的UUID （long，long）; 构造函数：

public static String getGuidFromByteArray(byte[] bytes) {
    ByteBuffer bb = ByteBuffer.wrap(bytes);
    long high = bb.getLong();
    long low = bb.getLong();
    UUID uuid = new UUID(high, low);
    return uuid.toString();
}

但是既然你不需要UUID对象，你可以做一个十六进制转储：

But since you don't need the UUID object, you can just do a hex dump:

public static String getGuidFromByteArray(byte[] bytes) {
    StringBuilder buffer = new StringBuilder();
    for(int i=0; i<bytes.length; i++) {
        buffer.append(String.format("%02x", bytes[i]));
    }
    return buffer.toString();
}

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