无法在基本类型char上调用equals（char） [英] Cannot invoke equals(char) on the primitive type char

问题描述

我是编程并尝试坚持基本猜谜游戏的新手，但我有这个错误。需要一些帮助，因为我已经将'猜测'设置为 char ，然后想要将它与字符数组进行比较，但尝试了几种不同的方法，但还没有快乐。

I'm new to programming and trying to nut out a basic guessing game, but I have this error. Need some help as I've set 'guess' to char, then want to compare it to the array of chars but tried a couple of different approaches but no joy yet.

它给出了底部if语句的错误：

It gives me the error on the if statement at the bottom containing:

(guess.equals(wordContainer[j]))

提前致谢。

我的代码：

import java.util.Scanner;  

public class GuessingGame {

    public static void main(String args[]) {

        Scanner keyboard = new Scanner(System.in);

        String wordArray[] = {"aardvarks", "determine", "different", "greatness", "miserable", "trappings", "valuables", "xylophone"};

        double rand = Math.random() * 8;
        int x = 0;      
        x = (int)rand;      

        System.out.println(x);

        String word = wordArray[x];
        int wordCount = word.length();

        System.out.println(word);
       // System.out.println(wordCount);

        char wordContainer[] = new char[wordCount];
        char wordHiddenContainer[] = new char[wordCount];

        String input;
        char guess;

        System.out.print("Enter your guess(a-z): ");
        input = keyboard.next();
        guess = input.charAt(0);

        for ( int i = 0 ; i < wordCount ; i++ ) {           
            wordContainer[i] = word.charAt(i);
            wordHiddenContainer[i] = '*';           
        }

        System.out.println(wordContainer);
        System.out.println(wordHiddenContainer);

        for (int j = 0; j <  word.length(); j++ ) {
            if(guess.equals(wordContainer[j])) {                
                wordHiddenContainer[j] = guess;

            }           
        }
    }   
}

推荐答案

将基元与 == 进行比较。如果将 char 转换为包装类 Character ，则可以使用 .equals （）。

Primitives are compared with ==. If you convert the chars to the wrapper classes Character, then you can use .equals().

更改

1. char guess; 到字符猜测;

或

if（guess.equals（wordContainer [j]）） to if（guess == wordContainer [j]））。

这篇关于无法在基本类型char上调用equals（char）的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！