Java - 按编号和字母拆分字符串 [英] Java - Split String by Number and Letters

问题描述

所以我有一个字符串，比如这个 C3H20IO

So I have, for example, a string such as this C3H20IO

我想做的就是拆分这个字符串所以我得到以下内容：

What I wanna do is split this string so I get the following:

Array1 = {C,H,I,O}
Array2 = {3,20,1,1}

1 作为 Array2 的第三个元素表示 I 元素的单原子性质。 O 也是如此。这实际上是我正在努力的部分。

The 1 as the third element of the Array2 is indicative of the monoatomic nature of the I element. Same for O. That is actually the part I am struggling with.

这是一个化学方程式，所以我需要根据它们的名称和原子数等来分离元素。 。

This is a chemical equation, so I need to separate the elements according to their names and the amount of atoms there are etc.

推荐答案

您可以尝试这种方法：

String formula = "C3H20IO";

//insert "1" in atom-atom boundry 
formula = formula.replaceAll("(?<=[A-Z])(?=[A-Z])|(?<=[a-z])(?=[A-Z])|(?<=\\D)$", "1");

//split at letter-digit or digit-letter boundry
String regex = "(?<=\\D)(?=\\d)|(?<=\\d)(?=\\D)";
String[] atoms = formula.split(regex);

输出：

原子：[C，3，H，20，I，1，O，1]

atoms: [C, 3, H, 20, I, 1, O, 1]

现在所有偶数指数均匀（0,2,4 ......）是原子，奇数是相关的数字：

Now all even even indices (0, 2, 4...) are atoms and odd ones are the associated number:

String[] a = new String[ atoms.length/2 ];
int[] n = new int[ atoms.length/2 ];

for(int i = 0 ; i < a.length ; i++) {
    a[i] = atoms[i*2];
    n[i] = Integer.parseInt(atoms[i*2+1]);
}

输出：

a：[C，H，I，O]

n：[3,20,1,1]

a: [C, H, I, O]
n: [3, 20, 1, 1]

这篇关于Java - 按编号和字母拆分字符串的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！