如何比较BigInteger的值作为循环中的条件？ [英] How do i compare values of BigInteger to be used as a condition in a loop?

问题描述

我试图比较一个BigInteger（base）的值是否>另一个BigInteger（prime）的值，以及'a'的值是否不等于1。如果a的值不是1，它应该突破循环。我该如何比较它们？

I am trying to compare if the value of one BigInteger(base) is > the value of another BigInteger(prime) and if the value of 'a' is not equal to one. If value of a is not 1, it should break out of the loop. How should i compare them?

 Random ran = new Random();
    BigInteger prime = new BigInteger(16,ran);
    BigInteger base,a,one;
    one = new BigInteger("1");

    for (int i = 0; i < 65535; i++){

        while (base>prime){
            base = new BigInteger(16,ran);
        }
        a = base.modPow(prime.subtract(one),prime);
        System.out.println("a: "+a);    
        if (a != one){
            break;          
        }   
    }

推荐答案

你可以使用 BigInteger.compareTo（BigInteger） 。

You can compare them using BigInteger.compareTo(BigInteger).

在您的情况下，这将是 while（base.compareTo（prime）> 0）{...} 。

In your case, this would be while (base.compareTo(prime) > 0) {...}.

此外，您的终止条件应该是从更改为if（a！= one）更改为 if（！a.equals（one）），因为两个 BigInteger 具有相同整数值的变量不一定引用同一个对象（这就是 == 和！= test）。

Also, your termination condition should be changed from if (a != one) to if (!a.equals(one)) since two BigInteger variables with the same integer value are not necessarily referencing the same object (which is all that == and != test).

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