任何Java“API”从XSD生成Sample XML？ [英] Any Java "API" to generate Sample XML from XSD?

问题描述

作为我们应用程序的一部分，我们需要开发一个接收XSD架构并提供示例XML的模块。 XSD架构将在运行时提供。那么有没有可以完成这项工作的Java API？

As part of our application we need to develop a module that takes in an XSD schema and gives out a sample XML. The XSD schemas will be supplied during runtime. So is there any Java API out there that can do the job?

搜索此论坛并找到以下类似问题。但讨论围绕着从XSD生成示例XML的工具。无法找到任何API参考。

how-to-generate-sample-xml-documents-from-dtd-or-xsd

tool-to-generate-xml-file-from-xsd-for-testing

xml-instance-generation-from-xml-schema-xsd

推荐答案

没有这样的API，但它是可能的。
'给出样本XML'意味着你必须从XSD基本类型实现样本XML节点的生成，如< xs：element name =valuetype =xs ：整数minOccurs =0/> ，处理minoccurs / maxoccurs属性，不在 xs：integer 节点等中存储日期等等。

There is no such API, but it's possible. 'gives out sample XML' means that you will have to implement generation of sample XML node(s) from XSD basic types like <xs:element name="value" type="xs:integer" minOccurs="0"/>, taking care of minoccurs/maxoccurs attributes, not storing dates in xs:integer nodes, etc, etc..

一旦完成，剩下的就不是问题了：用 XPath 或<$遍历XSD c $ c> org.w3c.dom。* ，展平复杂类型和扩展将起到作用。我打赌你会在发布问题后几分钟内在stackoverflow上收到工作遍历代码。

Once it's done, the rest is not a problem: traversing XSD with XPath or org.w3c.dom.*, flattening complex types and extensions will do the trick. I bet you'll receive working traversing code here on stackoverflow within minutes after posting question.

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