使用snakeYaml在根目录中解析带有映射的YAML文档 [英] Parsing a YAML document with a map at the root using snakeYaml
问题描述
我想将YAML文档读取到自定义对象的地图(而不是默认情况下snakeYaml执行的地图)。所以这个:
I want to read a YAML document to a map of custom objects (instead of maps, which snakeYaml does by default). So this:
19:
typeID: 2
limit: 300
20:
typeID: 8
limit: 100
将被加载到看起来像像这样:
Would be loaded to a map which looks like this:
Map<Integer, Item>
其中Item为:
class Item {
private Integer typeId;
private Integer limit;
}
我找不到办法用snakeYaml做到这一点,我无法'找到一个更好的任务库。
I could not find a way to do this with snakeYaml, and I couldn't find a better library for the task either.
该文档仅包含嵌套在其他对象中的maps / collections的示例,以便您可以执行以下操作:
The documentation only has examples with maps/collections nested inside other objects, so that you can do the following:
TypeDescription typeDescription = new TypeDescription(ClassContainingAMap.class);
typeDescription.putMapPropertyType("propertyNameOfNestedMap", Integer.class, Item.class);
Constructor constructor = new Constructor(typeDescription);
Yaml yaml = new Yaml(constructor);
/* creating an input stream (is) */
ClassContainingAMap obj = (ClassContainingAMap) yaml.load(is);
但是,当它位于文档的根目录时,如何定义Map格式?
But how do I go about defining the Map format when it is at the root of the document?
推荐答案
您需要添加自定义构造函数。但是,在您的情况下,您不希望注册item或item-list标记。
You need to add a custom Constructor. However, in your case you don't want register an "item" or "item-list" tag.
实际上,您想申请 Duck Typing 给你的Yaml。它不是超级高效的,但有一种相对简单的方法可以做到这一点。
In effect, you want to apply Duck Typing to your Yaml. It's not super efficient, but there is a relatively easy way to do this.
class YamlConstructor extends Constructor {
@Override
protected Object constructObject(Node node) {
if (node.getTag() == Tag.MAP) {
LinkedHashMap<String, Object> map = (LinkedHashMap<String, Object>) super
.constructObject(node);
// If the map has the typeId and limit attributes
// return a new Item object using the values from the map
...
}
// In all other cases, use the default constructObject.
return super.constructObject(node);
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