带有not()和ends-with()的Xpath错误 [英] Xpath error with not() and ends-with()
问题描述
我有以下Xpath表达式:
I have the following Xpath expression:
//*[not(input)][ends-with(@*, 'Copyright')]
我希望它能给我所有元素 - 输入除外 - 具有任何属性值以Copyright结尾。
I expect it to give me all elements - except input - with any attribute value which ends with "Copyright".
我在Selenium 2 Java API中使用 webDriver.findElements(By.xpath(expression))执行它
并收到以下错误:
I execute it in the Selenium 2 Java API with webDriver.findElements(By.xpath(expression))
and get the following error:
表达式不是合法的
表达式
The expression is not a legal expression
但这些表达式没有问题:
But these expressions work without trouble:
//*[not(input)][starts-with(@*, 'Copyright')]
//*[ends-with(@*, 'Copyright')]
任何想法?
推荐答案
我有以下Xpath表达式:
I have the following Xpath expression:
//*[not(input)][ends-with(@*, 'Copyright')]
我希望它能给我所有元素 -
除输入外 - 任何属性
值以Copyright结尾。
I expect it to give me all elements - except input - with any attribute value which ends with "Copyright".
有这里有几个问题:
-
ends-with()
只是一个标准的XPath 2.0函数,所以你可能正在使用XPath 1.0引擎并且它正确引发错误,因为它不知道一个名为的函数ends-with()
。
ends-with()
is a standard XPath 2.0 function only, so the chances are you are using an XPath 1.0 engine and it correctly raises an error because it doesn't know about a function calledends-with()
.
即使您使用的是XPath 2.0处理器,表达式也会结束(@ *, 'Copyright')
在一般情况下导致错误,因为 ends-with()
函数被定义为接受最多一个字符串( xs:string?
)作为两个操作数 - 但是 @ *
会产生一个包含多个字符串的序列元素具有多个属性的情况。
Even if you are working with an XPath 2.0 processor, the expression ends-with(@*, 'Copyright')
results in error in the general case, because the ends-with()
function is defined to accept atmost a single string (xs:string?
) as both of its operands -- however @*
produces a sequence of more than one string in the case when the element has more than one attribute.
// * [not(input)]
并不意味着选择所有未命名的元素输入
。真正的含义是:选择所有没有名为input的子元素的元素。
//*[not(input)]
doesn't mean "select all elements that are not named input
. The real meaning is: "Select all elements that dont have a child element named "input".
解决方案:
-
使用此XPath 2.0表达式:
// * [not(self :: input)] [@ * [ends-with(。,'Copyright')]]
如果是XPath 1.0使用以下表达式:
In the case of XPath 1.0 use this expression:
....
//*[not(self::input)]
[@*[substring(., string-length() -8) = 'Copyright']]
以下是使用XSLT对上一个XPath表达式的简短而完整的验证:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/*">
<xsl:copy-of select=
"//*[not(self::input)]
[@*[substring(., string-length() -8)
= 'Copyright'
]
]"/>
</xsl:template>
</xsl:stylesheet>
当此转换应用于以下XML文档时:
<html>
<input/>
<a x="Copyright not"/>
<a y="This is a Copyright"/>
</html>
生成所需的正确结果:
<a y="This is a Copyright"/>
如果XML文档位于默认命名空间:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:x="http://www.w3.org/1999/xhtml"
>
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/*">
<xsl:copy-of select=
"//*[not(self::x:input)]
[@*[substring(., string-length() -8)
= 'Copyright'
]
]"/>
</xsl:template>
</xsl:stylesheet>
:
<html xmlns="http://www.w3.org/1999/xhtml">
<input z="This is a Copyright"/>
<a x="Copyright not"/>
<a y="This is a Copyright"/>
</html>
产生了想要的正确结果:
<a xmlns="http://www.w3.org/1999/xhtml" y="This is a Copyright"/>
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