Java：在字符串中打印一个唯一的字符 [英] Java: Print a unique character in a string

问题描述

我正在编写一个程序，用于打印字符串中的唯一字符（通过扫描仪输入）。我已经创建了一个尝试完成此操作的方法，但我不断获取不重复的字符，而不是字符串唯一的字符（或字符）。我只想要这些独特的字母。

I'm writing a program that will print the unique character in a string (entered through a scanner). I've created a method that tries to accomplish this but I keep getting characters that are not repeats, instead of a character (or characters) that is unique to the string. I want the unique letters only.

这是我的代码：

import java.util.Scanner;
public class Sameness{
   public static void main (String[]args){
   Scanner kb = new Scanner (System.in); 
     String word = "";

     System.out.println("Enter a word: ");
     word = kb.nextLine();

     uniqueCharacters(word); 
}

    public static void uniqueCharacters(String test){
      String temp = "";
         for (int i = 0; i < test.length(); i++){
            if (temp.indexOf(test.charAt(i)) == - 1){
               temp = temp + test.charAt(i);
         }
      }

    System.out.println(temp + " ");

   }
}            

这里的示例输出如上代码：

And here's sample output with the above code:

Enter a word: 
nreena
nrea 

预期输出为： ra

推荐答案

根据您所需的输出，您必须替换最初在以后重复时添加的字符，因此：

Based on your desired output, you have to replace a character that initially has been already added when it has a duplicated later, so:

public static void uniqueCharacters(String test){
    String temp = "";
    for (int i = 0; i < test.length(); i++){
        char current = test.charAt(i);
        if (temp.indexOf(current) < 0){
            temp = temp + current;
        } else {
            temp = temp.replace(String.valueOf(current), "");
        }
    }

    System.out.println(temp + " ");

}

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