我应该如何在Java中使用getResource()? [英] How should I use getResource() in Java?

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问题描述

这个问题在很多地方被提出,有很多小的变化。 (例如 Java - getClassLoader()。getResource()驱使我疯狂等。)我仍然无法做到工作。

这是一段代码:

This question is asked in numerous places, with myriad small variations. (Such as Java - getClassLoader().getResource() driving me bonkers among others.) I still can't make it work.
Here's a code snippet:

        String clipName = "Chook.wav";
        ClassLoader classLoader = Thread.currentThread().getContextClassLoader();
        // URL url = classLoader.getResource(clipName);
        URL url = new URL("file:///Users/chap/Documents/workspace/the1620/bin/ibm1620/" + clipName);
        ais = AudioSystem.getAudioInputStream(url);

这有效 - 请注意我已经硬编码了包含剪辑文件的目录的路径,其中 与我的.class文件位于同一目录中。唉,注释掉的代码只返回url的空值。

This works -- note that I've hard-coded the path to the directory containing the clip file, which is there, and is in the same directory as my .class file. Alas, the commented-out code just returns a null value for url.

大多数其他帖子似乎都处理了getResourceAsStream()。我想我应该使用getResource()。 会有所不同吗?

Most other posts seem to deal with getResourceAsStream(). I think I'm supposed to be using getResource(). Is that making the difference?

只有不能这么难。有什么线索吗?

It just can't be this hard. Any clues?

推荐答案

String clipName = "Chook.wav";

当使用 getResource 时,你传递的字符串in必须是绝对名称或相对于某个类有效。由于您使用 ClassLoader.getResource()而不是 Class.getResource(),因此它必须是绝对路径。

When using getResource, the string you pass in must be either an absolute name or be valid relative to a certain class. Since you're using ClassLoader.getResource() and not Class.getResource(), it must be an absolute path.

如果没有看到你的实际文件层次结构,我只能猜测bin是你编译的类和资源的根,而ibm1260是一个包/文件夹在该路径中,Chook.wav存在于该文件夹中。如果是这种情况,那么你需要使用 /ibm1260/Chook.wav (或者可能 ibm1260 / Chook.wav ,我通常不使用类加载器进行资源查找)作为传递给 getResource()的文件的名称。

Without seeing your actual file hierarchy, I can only guess that "bin" is the root of your compiled classes and resources, and "ibm1260" is a package/folder within that path, and "Chook.wav" exists in that folder. If that's the case, then you need to use /ibm1260/Chook.wav (or potentially ibm1260/Chook.wav, I don't typically use the class loader for resource lookups) as the name of the file that you pass in to getResource().

无论哪种方式,您都需要确保将文件复制到已编译代码的位置,并确保根文件夹位于类路径中。

Either way, you need to make sure that the file is copied into the location of your compiled code and that the root folder is on the classpath.

这篇关于我应该如何在Java中使用getResource()?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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