将Java List转换为Scala Seq [英] Convert Java List to Scala Seq

问题描述

我需要在Java
中实现一个返回Seq的方法但是我遇到错误，我不知道如何解决它。

I need to implement a method that return a "Seq", in Java But I encounter an error, I don't know how to solve it.

java.util.ArrayList cannot be cast to scala.collection.Seq

这是我到目前为止的代码

Here is my code so far

@Override
public Seq<String> columnNames() {
    List<String> a = new ArrayList<String>();
    a.add("john");
    a.add("mary");
    Seq<String> b = (scala.collection.Seq<String>) a;
    return b;
}

scala.collection.JavaConverters。似乎没有提供转换为 Seq 的可能性。
谢谢

scala.collection.JavaConverters. doesn't seem to offer the possibility to convert as a Seq. Thank you

推荐答案

JavaConverters是我需要解决的问题。

JavaConverters is what I needed to solve this.

import scala.collection.JavaConverters;

public Seq<String> convertListToSeq(List<String> inputList) {
    return JavaConverters.asScalaIteratorConverter(inputList.iterator()).asScala().toSeq();
}

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