正则表达式替换重复的字符 [英] Regex to replace repeated characters

问题描述

有人可以给我一个Java正则表达式来替换以下内容吗。

Can someone give me a Java regex to replace the following.

如果我有这样的单词Cooooool，我需要将其转换为Coool 3点钟。所以我可以用正常的单词酷来区分它。

If I have a word like this "Cooooool", I need to convert this to "Coool" with 3 o's. So that I can distinguish it with the normal word "cool".

另一个例子：happyyyyyy应该是happyyy

Another ex: "happyyyyyy" should be "happyyy"

replaceAll("(.)\\1+","$1"))

我尝试了这个，但它删除了所有重复的字符，只剩下一个。

I tried this but it removes all the repeating characters leaving only one.

推荐答案

改变你的正则表达式如下。

Change your regex like below.

string.replaceAll("((.)\\2{2})\\2+","$1");

• （第一个caturing组的开始。


• （。）捕获任何字符。对于这种情况，你可以使用 [az]


• \\2 指第二个捕获组。 \\2 {2} 必须重复两次。


• ）第一个捕获组结束。所以这将捕获前三个重复字符。


• \\2 + 重复第二组一次或多次。


• ( start of the first caturing group.
• (.) captures any character. For this case, you may use [a-z]
• \\2 refers the second capturing group. \\2{2} which must be repeated exactly two times.
• ) End of first capturing group. So this would capture the first three repeating characters.
• \\2+ repeats the second group one or more times.

DEMO

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