Tomcat 7一直给我404.我做错了什么？ [英] Tomcat 7 keeps giving me a 404. What am I doing wrong?
问题描述
这是我的第一个servlet。这是它的代码。
this is my first servlet ever. here is it's code.
import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
public class Ch1Servlet extends HttpServlet {
public void doGet(HttpServletRequest request, HttpServletResponse response) throws IOException {
PrintWriter out = response.getWriter();
java.util.Date today = new java.util.Date();
out.println("<html> " +"<body>" +"<h1 align=center>HF\'s Chapter1 Servlet</h1>" +" " + "<br>" + today + "</body>" + "</html>");
}
}
我使用此命令编译它
javac -classpath /usr/share/tomcat7/common/lib/servlet-api.jar -d classes src / Ch1servlet.java
然后我放了我的WEB-INF文件夹中的classes文件夹中的 .class 文件。
I compiled it using this command
javac -classpath /usr/share/tomcat7/common/lib/servlet-api.jar -d classes src/Ch1servlet.java
I then put the .class file in the classes folder in my WEB-INF folder.
这是我的web.xml
Here is my web.xml
<?xml version="1.0" encoding="ISO-8859-1" ?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4">
<servlet>
<servlet-name>Chapter1 Servlet</servlet-name>
<servlet-class>Ch1Servlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Chapter1 Servlet</servlet-name>
<url-pattern>/Serv1</url-pattern>
</servlet-mapping>
</web-app>
Tomcat7在 http://127.0.0.1上给我一个404： 8080 / ch1 / Serv1 / 说请求的资源（/ ch1 / Serv1 /）不可用。
Tomcat7 keeps giving me a 404 on http://127.0.0.1:8080/ch1/Serv1/ saying The requested resource (/ch1/Serv1/) is not available.
文件树：
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我在这里做错了什么？
推荐答案
您应该将servlet类放在一个包中。无包装servlet是否有效取决于较旧的Tomcat和JVM版本的特定组合。如果你在书/教程中看到这个例子，那肯定是过时了。
You should put servlet classes in a package. Whether packageless servlets works depend on the specific combination of an older Tomcat and JVM version. If you see this example in a book/tutorial, then it is surely far outdated.
package com.example;
// ...
public class Ch1Servlet extends HttpServlet {
// ...
}
你应该有一个 /com/example/Ch1Servlet.java 文件。编译如下
You should have a /com/example/Ch1Servlet.java file. Compile it as follows
javac -classpath /usr/share/tomcat7/common/lib/servlet-api.jar -d classes src/com/example/Ch1servlet.java
（I但是想知道常见 lib在那里做什么，这对于Tomcat 4.x / 5.x来说是典型的，但是从Tomcat 6开始它就不存在了。如果你手动改变了Tomcat的结构为了遵循过时教程的说明，撤消吧！）
(I however wonder what the common lib is doing there, this was typical for Tomcat 4.x/5.x, but it's not present since Tomcat 6. If you manually changed Tomcat's structure in order to follow the instructions of an outdated tutorial, undo it!)
放入 com 包含您在webapp的 / WEB-INF / classes 文件夹中的生成类的文件夹。所以你必须有 /WEB-INF/classes/com/example/Ch1Servlet.class 。
Put the com folder with the generated class by its entirity in /WEB-INF/classes folder of your webapp. So you must have a /WEB-INF/classes/com/example/Ch1Servlet.class.
然后，编辑 /WEB-INF/web.xml 以在< servlet-class>中指定servlet类的完全限定名称（FQN） / code>：
Then, edit your /WEB-INF/web.xml to specify the fully qualified name (FQN) of the servlet class in <servlet-class>:
<?xml version="1.0" encoding="UTF-8"?>
<web-app
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
version="3.0"
>
<servlet>
<servlet-name>Chapter1 Servlet</servlet-name>
<servlet-class>com.example.Ch1Servlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Chapter1 Servlet</servlet-name>
<url-pattern>/Serv1</url-pattern>
</servlet-mapping>
</web-app>
（请注意我修复了根声明以符合Tomcat 7支持的servlet版本，否则它将回归到最低兼容性模式）
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