使用两个for循环计算字符串中的字母 [英] Counting letters in a string using two for-loops

问题描述

我必须读取字符串hello world并仅使用for循环输出每个字母的频率。教练暗示我需要使用两个循环并给我们开始以下代码：

I have to read the string "hello world" and output each letter's frequency using only for loops. The instructor hinted that I'd need to use two loops and gave us the following code to begin:

int ch, count;
for (ch ='a'; ch <='z'; ch++) {
  //count the number of occurrences in a line
  //Print the count>0
}

编辑：我认为我会犯这个问题发布我一年前发现的解决方案，因为这个问题已经得到了相当多的点击率。

I figured I'd necro this question and post the solution I found a year ago due to the fact that this question has been getting a decent amount of hits.

int count;
int value;
for (int i=65; i<91; i++) {
    count=0;
    for (int j=0; j<S.length; j++) {
        value=(int)S[j];
        if (value == i) {
             count++;
        }
    }
    if (count>0) 
       System.out.println((char)i+" -- "+count);
}

推荐答案

int count;
int value;
   for (int i=65; i<91; i++) {
      count=0;
      for (int j=0; j<S.length; j++) {
      value=(int)S[j];
      if (value == i) {
         count++;
      }
   }
   if (count>0) 
      System.out.println((char)i+" -- "+count);
}

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