如何解析不带引号的JSON字符串 [英] how to parse unquoted JSON string

问题描述

我有一个JSON字符串，其中没有引用键和值，我想将其转换为格式正确的JSON。

I have a JSON string where neither the keys nor the values are quoted and I would like to transform it to a correctly formatted JSON.

{basic:{0:{index:0, license:t, nameSID:n, image:"img_left", descriptionSID:t, category:r}}

是否有可以处理它的Java库？我试过杰克逊但它不起作用。

Is there a Java library that could handle it? I tried Jackson but it does not work.

问候，
Jan

regards, Jan

推荐答案

您可以使用 JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES 与杰克逊允许不带引号的字段名称：

You can use JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES with Jackson to allow unquoted field names:

JsonFactory factory = new JsonFactory();
factory.configure(JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES, true);
JsonParser jp = factory.createJsonParser(new FileInputStream("content.json"));

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