检查每个字符的数字 [英] Checking each character for a number

问题描述

我正在尝试循环一个字符串并检查每个字符，如果其中一个字符是数字。如果是数字，我想将其恢复为真。我有一个字符串崩溃，虽然它返回true（它有一个数字）。

I am trying to loop through a string and check each character if one of the characters is a number. If it is a number, I want to return it as true. I have a string "crash", though it returns it as true (that it has a number).

这是我到目前为止所拥有的：

Here's what I have so far:

public boolean isNumber()
{
  String newString = "crash";
  boolean isNumber = true;
  for (int i=0; i<newString.length(); i++)
  {
     if (Character.isDigit(newString.charAt(i)))
     {
        isNumber = true;
        continue; // continue looping through the string. Go on to the next index.
                  // The character at index i is a number.
     }
     else
     {
        isNumber = false; 
        break; // terminate the for-loop and return it as false! It is not a number!
     }
   }
  return isNumber;
}

我无法弄清楚出了什么问题。我的逻辑似乎很好，但我的编码不是。

I can't figure out what's wrong. My logic seems to be fine, but my coding isn't.

编辑：我明白了。感谢您的帮助！

I figured it out. Thanks for all your help!

推荐答案

我刚刚运行该代码，我得到 false ，如预期的那样。请仔细检查您是否正确运行。

I just ran that code and I get false, as expected. Please double-check that you’re running it correctly.

顺便说一下，这是一种表达该功能的简单方法：

Here’s a simpler way to express that function, by the way:

public boolean isNumber(String string) {
  for (int i = 0; i < string.length(); i++) {
    if (!Character.isDigit(string.charAt(i))) {
      return false;
    }
  }

  return true;
}

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