将一串二进制解析为文本/字符 [英] Parsing a string of binary into text/characters

问题描述

我可能忽视了一些愚蠢的事情，但我从来没有在代码中处理过二进制文件，并认为在加密程序中练习它是个好主意。
长话短说，我能够将字符串转换为二进制（以字符串的形式），但无法弄清楚如何反向。

I am probably overlooking something silly, but I've never had to deal with binary in code and thought it'd be a good idea to practice it in an encryption program, for kicks. Long story short, I'm able to convert a string into binary (in the form of a string), but can't figure out how to do the reverse.

现在，我有这样的事情：

Right now, I have something like this:

public static String bytesToString(String bytes){
    int i = bytes.length()/8;
    int pos = 0;
    String result = "";
    for(int j=0; j<i; j++){
        String temp = bytes.substring(pos,pos+8);
        byte b = (byte) Integer.parseInt(temp);
        result = result + Byte.toString(b);
        pos++;
    }
    System.out.println("Result: " + result);
    return result;
}

我认为字节被解析为文字数字。我错过了什么？
编辑：为了澄清，我先前已经将一串文本解析成位并将它们写成字符串。我想将此字符串拆分为字节并将其解析为字母。这将需要011010000110010101111001并返回嘿。

I think the bytes are being parsed as literal numbers. What am I missing? To clarify, I will previously have parsed a string of text into bits and written them to a string. I want to split this string into bytes and parse them back into letters. It would take "011010000110010101111001" and return "hey".

推荐答案

如何使用 Integer.parseInt（文字，2） ？如，

How about using Integer.parseInt(text, 2)? As in,

public static int binaryToInt(String binary)
{
    return Integer.parseInt(binary, 2);
}

我不知道为什么你的 binaryToString 方法都需要和返回一个字符串。

I'm not sure why your binaryToString method both takes and returns a string.

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