将绝对文件路径从java代码传递给xslt document() [英] Pass absolute file path from java code to xslt document()
问题描述
在我的xslt中,我想查找一个xml文件。我需要从java代码传递这个文件的路径。我有以下内容:
In my xslt I'd like to look up an xml file. I need to pass the path to this file from java code.I have the followings:
...
Transformer transformer = TRANSFORMER_FACTORY.newTransformer();
transformer.setParameter("mypath", "/home/user/repository");
xslt:
<?xml version="1.0"?>
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" indent="yes"/>
<xsl:param name="mypath"/>
...
<xsl:template match="connection[@id]">
<xsl:variable name="lookupStore" select="document('$mypath/myfile.xml')/connections"/>
<xsl:copy>
<xsl:apply-templates select="$lookupStore">
<xsl:with-param name="current" select="."/>
</xsl:apply-templates>
</xsl:copy>
</xsl:template>
...
<xsl:transform>
问题是我想传递一个绝对的基本路径到xsl,我想要的与实际的xml文件名(myfile.xml)结合使用。在我看来, document
会考虑相对于xsl位置的文件参数。
此外,我注意到该参数未从java代码中获取。我使用JABX和默认的Xalan XSLT处理器(1.0)
我尝试了很多基于其他SO帖子传递参数的变体,但没有成功。
The problem is that I want to pass an absolute "base" path to the xsl, which I want to combine with the actual xml file name (myfile.xml). It seems to me that document
considers file parameters relative to the location of the xsl.
Furthermore I remarked that the parameter is not picked up from the java code. I use JABX with the default Xalan XSLT processor (1.0)
I tried many variations of passing the parameters based on the other SO posts, but no success.
推荐答案
您需要使用完整的文件URL构造一个字符串: document(concat('file://',$ mypath,'/ myfile.xml') )
。
You need to construct a string then with the complete file URL: document(concat('file://', $mypath, '/myfile.xml'))
.
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