在Java中拆分字符串与空元素 [英] Splitting String in Java with empty elements

问题描述

我正在逐行读取.csv文件。一行可以看例如下： String str =10,1 ,,,,。

I'm reading from a .csv File line by line. One line could look for example as following: String str = "10,1,,,,".

现在我想根据，拆分： String [] splitted = str.split（，）; 现在的问题是这只会产生2个元素但我希望有5个元素，前两个元素应该包含10个和1个，另外3个应该只是一个空字符串。

Now I would like to split according to ",": String[] splitted = str.split(","); The problem now is that this only results in 2 elements but I would like to have 5 elements, the first two elements should contain 10 and 1 and the other 3 should be just an empty String.

另一个例子是 String str =0 ,,,,,只产生一个元素，但我希望有5个元素。

Another example is String str = "0,,,,," which results in only one element but I would like to have 5 elements.

最后一个例子是 String str =9 ,,, 1，，它给出了2个元素（9和1），但我希望有5个元素。第一个元素应该是9，第四个元素应该是1，所有其他元素应该是一个空字符串。

The last example is String str = "9,,,1,," which gives 2 elements (9 and 1), but I would like to have 5 elements. The first element should be 9 and the fourth element should be 1 and all other should be an empty String.

如何做到这一点？

推荐答案

您需要将它与 -1 参数一起使用

You need to use it with -1 parameter

String[] splitted = str.split(",", -1);

之前已经讨论过，例如：
Java：String split（）：我希望它在末尾包含空字符串

This has been discussed before, e.g. Java: String split(): I want it to include the empty strings at the end

但是 split 真的不应该解析csv的方式，当你有一个包含逗号的字符串值时，你可能会遇到问题

But split really shouldn't be the way you parse a csv, you could run into problems when you have a String value containing a comma

23,"test,test","123.88"

split 会将该行拆分为4个部分：

split would split the row into 4 parts:

[23, "test, test", "123.88"]

我不认为你想要那样。

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