获取带日期和尾随计数器的文件名 [英] Get filename with date and trailing counter

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本文介绍了获取带日期和尾随计数器的文件名的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我需要将文件名框架为 name_< date> _N ,其中N是类似文件数量的计数器。

I need to frame a file name as name_<date>_N, where N is a counter for the number of similar files.

String fileName = "name";
String fileNameWithDate = fileName + "_"+ new SimpleDateFormat("MMM_dd_yyyy").format(cal.getTime());

如果我尝试在给定日期下载更多次,则计数应增加1;例如, name_Dec_10_2015_N 。如何获取带日期的文件名并增加1?

If I try to download more times for a given date, the count should be incremented by 1; for example, name_Dec_10_2015_N. How do I get filename with date and incremented by 1?

推荐答案

正如@MadProgrammer已编写的那样,您需要按照以下步骤进行操作

As @MadProgrammer already wrote you need to do it in following steps


  • 获取与您的模式匹配的所有文件的列表

  • 查找具有最高计数器的文件

  • 为增加的计数器创建了文件名

这是一个简短的片段,您可以将其用作一个起点(处理边缘情况,如:没有找到文件等,有意省略并且是你自己工作的一部分)

Here is short snippet which you can use as a starting point (the handling of edge cases, like: no file found, etc., are intentionally omited and part of your own work)

public class IncreaseCounter {

    static final SimpleDateFormat FILE_DATE = new SimpleDateFormat("MMM_dd_yyyy");

    public static void main(String[] args) {

        // filter files which matches the given pattern
        FilenameFilter fileNameFilter = new FilenameFilter() {
            @Override
            public boolean accept(File dir, String name) {
                return name.matches("^name_..._.._.....*\\.txt");
            }
        };

        // needed to sort the file list based on the file counter
        Comparator<File> sortByCounter = new Comparator<File>() {
            @Override
            public int compare(File file1, File file2) {
                return getFileCounter(file1.getName()) - getFileCounter(file2.getName());
            }
        };

        String filesLocation = "resources/";
        int highestCounter = 0;

        // read the files matching the filter
        File[] listFiles = new File(filesLocation).listFiles(fileNameFilter);
        List<File> files = Arrays.asList(listFiles);

        // sort the files by their file counter
        Collections.sort(files, sortByCounter);

        // get the highest counter
        String fileWithHighestCounter = files.get(files.size() - 1).getName();
        highestCounter = getFileCounter(fileWithHighestCounter);

        String nextFileName = String.format("name_%s_%d.txt",
                FILE_DATE.format(new Date()), 
                highestCounter + 1
        );

        System.out.println("nextFileName = " + nextFileName);
    }

    /**
     * Extract the file counter.
     * @param fileName the file name
     * @return 0 - if the file has no counter, otherwise the counter value
     */
    static int getFileCounter(String fileName) {
        String namePatternWithCounter = "^name_..._.._...._*(.*)\\.txt";
        String counterString = fileName.replaceAll(namePatternWithCounter, "$1");
        if (counterString.isEmpty()) {
            return 0;
        }
        return Integer.parseInt(counterString);
    }
}

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