如何让应用等待，然后开始活动或回去？ [英] How to make app wait and then start activity or go back?

问题描述

我希望我的活动显示3秒的屏幕，然后返回上一屏幕。但是当我使用

I want my activity to show a screen for 3 seconds, then go back to previous screen. But when i use

protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.welcome_layout);
        TextView tvResult = (TextView)findViewById(R.id.textView1)
        Thread.sleep(3000);
            Intent i = new Intent(this,myActivity.class);
            startActivity(i);

但不幸的是，这不起作用。此事件显示活动等待3秒后返回。但是，我希望它在返回之前显示其内容。我该怎么办？

But unfortunately, this does not work. This doesent show the activity waits 3 seconds and goes back. However, i want it to show its contents before going back. How can i do it ?

推荐答案

你应该删除这个 Thread.sleep（3000）; 阻止ui线程。你永远不应该阻止ui thred。您可以使用Handler post延迟延迟，然后startActivtiy。

You should remove this Thread.sleep(3000); which block the ui thread. You should never block the ui thred. You can use a Handler postDelayed with a delay and then startActivtiy.

Handler handler = new Handler();
handler.postDelayed(new Runnable(){
@Override
  public void run(){
   // do something
 }
 }, 3000);

要返回上一个活动，您可以致电 finish（）。

To go back to previous Activity you can call finish().

此外，如果您需要返回上一个活动3秒，为什么还需要

Also if you need to go back to the previous activity for 3 seconds why do you need

Intent i = new Intent(this,myActivity.class);
startActivity(i);

调用完成（）将完成工作

这篇关于如何让应用等待，然后开始活动或回去？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！