如何访问变量的原始值 [英] how to access original value of the variable

问题描述

假设我有这段代码

public static long number;
public static void main(String args[]) {
    String str1 = args[0];
    System.out.println("str1 is = " + str1);
    long number = Long.parseLong(str1);
    System.out.println("number value is = " + number);
}

public static void test1(){
    System.out.println("number value inside test1 is = " + number);
}

假设我将12345作为参数传递，所以我的o / p将是

Say I pass 12345 as argument, so my o/p will be

 str1 is  12345
 number value is  12345
 number value inside test1 is  0

我想要的是能够在test1方法中访问arg [0]（用户参数）或数字（12345）的原始值同样。请帮我做。谢谢。！

What I want is to be able to access arg[0] (user argument) or original value of number (12345) inside test1 method as well. Pls help me do it. Thanks.!

推荐答案

将您的班级编号设置为已解析值 str1 。目前，您设置的本地字段没有超出main方法的范围。

Set your class-level number to the parsed value of str1. Currently, you set a local field which has no scope beyond the main method.

使用：

number = Long.parseLong(str1);

而不是：

long number = Long.parseLong(str1);

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