为什么数组没有在javacode下面排序？ [英] why array is not sorted in below javacode?

问题描述

当我运行代码时，数组p没有排序。我无法弄清楚

when i run the code ,array p is not sorted. I cant figure out

为什么会发生这种情况？

why is this happening?

import java.util.Arrays;

public class Main {

    public static void main (String[] args){

        //creating array p
        int[] p= new int[] {2,7,8,3,9,1,4,5,6,0 };

        //sort p[5] to p[9]
        Arrays.sort(p, 5, 9);
        for(int l=0;l<p.length;l++)
        {
            System.out.print(p[l]);
        }

    }
}

输出是：2783914560

output is:2783914560

推荐答案

您特别要求对p [5]到p [9] 独占的部分进行排序的上限...所以4个元素，已经按顺序排列（1,4,5,6）。

You're specifically asking to sort the portion from p[5] to p[9] exclusive of the upper bound... so 4 elements, which are already in order (1, 4, 5, 6).

如果你想排序要p [9] 包含，你应该致电

If you want to sort to p[9] inclusive, you should call

Arrays.sort(p, 5, 10);

来自文档：

toIndex - 要排序的最后一个元素的索引

toIndex - the index of the last element, exclusive, to be sorted

当然，仍然不会对整个数组进行排序 - 只是它的最后一部分，所以你最终会得到{2,7,8,3,9,0,1 ，4,5,6}。要对整个数组进行排序，只需调用 Arrays.sort（p）。

Of course, that still won't sort the whole array - just the last part of it, so you'd end up with { 2, 7, 8, 3, 9, 0, 1, 4, 5, 6 }. To sort the whole array, just call Arrays.sort(p).

请注意指定a的模式使用包含下限和独占上限的范围在计算中是常见的非常，你应该习惯它。另一个常见的例子是 String.substring ：

Note that the pattern of specifying a range using an inclusive lower bound and an exclusive upper bound is very common in computing, and you should get used to it. Another common example is String.substring:

String text = "0123456789";
String substring = text.substring(0, 5); // 01234

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