如何将日文字符分类为汉字或假名？ [英] How to classify Japanese characters as either kanji or kana?

问题描述

鉴于以下文字，我如何将每个角色分类为假名或汉字？

Given the text below, how can I classify each character as kana or kanji?

谁か确认上记これらのフ

誰か確認上記これらのフ

要得到这样的东西

誰 - kanji
か - kana
確 - kanji
認 - kanji 
上 - kanji 
記 - kanji 
こ - kana 
れ - kana
ら - kana
の - kana
フ - kana

（对不起，如果我做的话）这是错误的。）

(Sorry if I did it incorrectly.)

推荐答案

此功能内置于 Character.UnicodeBlock 类。与日语相关的Unicode块的一些示例：

This functionality is built into the Character.UnicodeBlock class. Some examples of the Unicode blocks related to the Japanese language:

Character.UnicodeBlock.of('誰') == CJK_UNIFIED_IDEOGRAPHS
Character.UnicodeBlock.of('か') == HIRAGANA
Character.UnicodeBlock.of('フ') == KATAKANA
Character.UnicodeBlock.of('ﾌ') == HALFWIDTH_AND_FULLWIDTH_FORMS
Character.UnicodeBlock.of('！') == HALFWIDTH_AND_FULLWIDTH_FORMS
Character.UnicodeBlock.of('。') == CJK_SYMBOLS_AND_PUNCTUATION

但是，与往常一样，魔鬼在细节中：

But, as always, the devil is in the details:

Character.UnicodeBlock.of('Ａ') == HALFWIDTH_AND_FULLWIDTH_FORMS

其中 A 是全角字符。因此，这与上面的半宽Katakana フ属于同一类别。请注意，全宽 A 与正常（半角）不同 A ：

where Ａ is the full-width character. So this is in the same category as the halfwidth Katakana ﾌ above. Note that the full-width Ａ is different from the normal (half-width) A:

Character.UnicodeBlock.of('A') == BASIC_LATIN

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