如何从hashmap中获取5个最高值？ [英] How to get 5 highest values from a hashmap?

问题描述

我有一个Hashmap链接存储为键的zipcodes和作为值存储在hashmap中的填充。

I have a Hashmap that links a zipcodes stored as keys and population stored as values in a hashmap.

hashmap包含大约33k个条目。

The hashmap contains around 33k entries.

我正试图从5个邮政编码中获取5个最高人口值，并打印出与5个最高人口相关联的5个邮政编码，但我无法理解如何算法要做到这一点。

I'm trying to get the 5 highest population values from 5 zip codes and print out the 5 zip codes ASSOCIATED with the 5 highest population, but I'm having trouble understanding the algorithm of how to do it.

如果它只是一个，那么它很容易但是5限制给了我一些麻烦。

If it was just one, its easy but the 5 restriction is giving me some trouble.

我知道将5个值存储在一个int数组中，并且我有一个计数器来确定它们中何时存储了5个，但就是这样。

I know to store the 5 values in an int array and I have a counter to determine when 5 of them are stored, but thats it.

谢谢

    int populatedCounter = 0;

    int[] populatedZip = new int[5];

    it = zipCodePop.entrySet().iterator();
    while (it.hasNext())
    {
        Map.Entry pairs = (Map.Entry)it.next();

        for (int i = 0; i < populatedZip.length; i++)
        {

        }
    }

}

推荐答案

将这样的条目放入列表和排序是一种选择。但33k元素是一个数字，其中排序的O（n * log（n））复杂性可能已经具有显着的性能影响。

Putting the entries of such a set into a list and sorting it is one option. But 33k elements is a number where the O(n*log(n)) complexity of sorting might already have a noticable performance impact.

一个apporach就是使用nr4bt已经提到的PriorityQueue（我回答时写了这个片段）。它基本上将所有元素插入到PriorityQueue中，该PriorityQueue根据映射条目的值进行排序。

One apporach would be to employ the PriorityQueue that nr4bt already mentioned (I wrote this snippet while he answered). It basically inserts all elements into a PriorityQueue that is sorted according to the values of the map entries.

import java.util.ArrayList;
import java.util.Comparator;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import java.util.Map.Entry;
import java.util.PriorityQueue;

public class GreatestOfMap
{
    public static void main(String[] args)
    {
        Map<String, Integer> map = new HashMap<String, Integer>();

        map.put("zip000", 1234);
        map.put("zip001", 2345);
        map.put("zip002", 3456);
        map.put("zip003", 4567);
        map.put("zip004", 5678);
        map.put("zip005", 6789);
        map.put("zip006", 123);
        map.put("zip007", 234);
        map.put("zip008", 456);
        map.put("zip009", 567);
        map.put("zip010", 7890);
        map.put("zip011", 678);
        map.put("zip012", 789);
        map.put("zip013", 890);

        int n = 5;
        List<Entry<String, Integer>> greatest = findGreatest(map, 5);
        System.out.println("Top "+n+" entries:");
        for (Entry<String, Integer> entry : greatest)
        {
            System.out.println(entry);
        }
    }

    private static <K, V extends Comparable<? super V>> List<Entry<K, V>> 
        findGreatest(Map<K, V> map, int n)
    {
        Comparator<? super Entry<K, V>> comparator = 
            new Comparator<Entry<K, V>>()
        {
            @Override
            public int compare(Entry<K, V> e0, Entry<K, V> e1)
            {
                V v0 = e0.getValue();
                V v1 = e1.getValue();
                return v0.compareTo(v1);
            }
        };
        PriorityQueue<Entry<K, V>> highest = 
            new PriorityQueue<Entry<K,V>>(n, comparator);
        for (Entry<K, V> entry : map.entrySet())
        {
            highest.offer(entry);
            while (highest.size() > n)
            {
                highest.poll();
            }
        }

        List<Entry<K, V>> result = new ArrayList<Map.Entry<K,V>>();
        while (highest.size() > 0)
        {
            result.add(highest.poll());
        }
        return result;
    }
}

这篇关于如何从hashmap中获取5个最高值？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！