如何在我的Spring MVC Web应用程序中添加.jsp页眉和页脚？ [英] How do I add .jsp headers and footers to my Spring MVC web app?
问题描述
如何将.jsp页眉和页脚添加到我的Spring MVC网页应用程序？
How do I add .jsp headers and footers to my Spring MVC web app?
我知道有很多不同的答案，但我想知道（它们都是真的，但更重要的是）这样做的正确方法是什么？我只是在学习Spring，我有一个提示答案就在于HandlerInterceptor。现在，我可能只是这样做.jsp包括。即使有这个包含解决方案，你能详细说明我在哪里放置页眉/页脚结构吗？任何建议或方向都会很棒。
I know there's many different answers, but I would like to know (them all really but more importantly) what is the proper way to do this? I'm just learning Spring and I have a hint the answer lies with HandlerInterceptor. For now, I might just do so .jsp includes. Even with this include solution, could you detail where I would place the headers/footers structurally? Any advice or direction would be great.
推荐答案
我在研究时发现了你的问题:-)不确定我的解决方案是否< good |坏|一个黑客|已经存在> 或者如果有更好的方法，但它适用于我当前的项目。
I found your question whilst researching :-) Not sure if my solution is <good | bad | a hack | already exists> or if there is a better way but it's working for my current project.
在 myapp-中servlet.xml 您可以使用自己的实现扩展viewResolver viewClass ：
In your myapp-servlet.xml you can extend the viewResolver viewClass with your own implementation:
<bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"
p:viewClass="com.my.app.view.JstlView"
p:prefix="/WEB-INF/views/"
p:suffix=".jsp"/>
通过覆盖renderMergedOutputModel，您可以强制所有视图真正成为模板您可以在其中定义全局布局，然后只需< jsp：include /> 您的部分。
By overriding the renderMergedOutputModel you can force all views to really be a template in which you can define your global layout and then simply <jsp:include/> your partial(s).
package com.my.app.view;
import java.util.*;
import org.springframework.web.servlet.view.InternalResourceView;
import javax.servlet.RequestDispatcher;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class JstlView extends InternalResourceView {
@Override
protected void renderMergedOutputModel(Map<String, Object> model, HttpServletRequest request, HttpServletResponse response) throws Exception {
String dispatcherPath = prepareForRendering(request, response);
// set original view being asked for as a request parameter
request.setAttribute("partial", dispatcherPath.substring(dispatcherPath.lastIndexOf("/") + 1);
// force everything to be template.jsp
RequestDispatcher rd = request.getRequestDispatcher("/WEB-INF/views/template.jsp");
rd.include(request, response);
}
}
如果你看看Spring的 InternalResourceView.java 在确定要使用的视图时，您将更好地了解Spring正在做什么。
If you look Spring's InternalResourceView.java you'll get a better idea of what Spring is doing when determining what view to use.
<!doctype html>
<html lang="en">
<head></head>
<body>
<header>
<jsp:include page="header.jsp"/>
</header>
<jsp:include page="${partial}"/>
<footer>
<jsp:include page="footer.jsp"/>
</footer>
</body>
</html>
如何使用EL获取JSP中的request / session / servletcontext属性？帮助我获取属性值 $ {partial} out。
How to obtain request / session / servletcontext attribute in JSP using EL? helped me here with getting the attribute value ${partial} out.
<p>I'm a partial!</p>
然后在控制器中，返回 simple_partial 查看
Then in a controller, return the simple_partial view
package com.my.app.controller;
import org.springframework.stereotype.Controller;
import org.springframework.beans.factory.annotation.Value;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
@Controller
@RequestMapping(value="/")
public class App{
@RequestMapping(method = RequestMethod.GET)
public String index() {
return "simple_partial";
}
}
将被
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