Java中的AES-256-CBC [英] AES-256-CBC in Java

问题描述

我正在尝试编写一个简单的Java程序，它将使用 AES-256-CBC 加密纯文本。有课程：

I'm trying to write a simple Java program that will encrypt plain text with AES-256-CBC. There is class:

import javax.crypto.Cipher;
import javax.crypto.spec.IvParameterSpec;
import javax.crypto.spec.SecretKeySpec;

public class AesCBC {
    private byte[] key;
    private byte[] iv;

    private static final String ALGORITHM="AES";

    public AesCBC(byte[] key, byte[] iv) {
        this.key = key;
        this.iv = iv;
    }

    public byte[] encrypt(byte[] plainText) throws Exception{
        SecretKeySpec secretKey=new SecretKeySpec(key,ALGORITHM);
        IvParameterSpec ivParameterSpec=new IvParameterSpec(iv);
        Cipher cipher=Cipher.getInstance("AES/CBC/PKCS5Padding");
        cipher.init(Cipher.ENCRYPT_MODE,secretKey,ivParameterSpec);
        return cipher.doFinal(plainText);
    }

    public byte[] getKey() {
        return key;
    }

    public void setKey(byte[] key) {
        this.key = key;
    }

    public byte[] getIv() {
        return iv;
    }

    public void setIv(byte[] iv) {
        this.iv = iv;
    }
}

有可能使用：

byte[] test="a".getBytes();

byte[] key=DatatypeConverter.parseHexBinary("b38b730d4cc721156e3760d1d58546ce697adc939188e4c6a80f0e24e032b9b7");
byte[] iv=DatatypeConverter.parseHexBinary("064df9633d9f5dd0b5614843f6b4b059");
AesCBC aes=new AesCBC(key,iv);
try{
    String result=DatatypeConverter.printBase64Binary(aes.encrypt(test));
    System.out.println(result);
}catch(Exception e){
    e.printStackTrace();
}

我的输出是 VTUOJJp38Tk + P5ikR4YLfw == ，但是当我执行此命令时：

My output is VTUOJJp38Tk+P5ikR4YLfw==, but when I execute this command:

/usr/bin/openssl enc -A -aes-256-cbc -base64 -K "b38b730d4cc721156e3760d1d58546ce697adc939188e4c6a80f0e24e032b9b7" -iv "064df9633d9f5dd0b5614843f6b4b059" <<< "a"

我得到的东西不同于Java程序（ Y65q9DFdR3k1XcWhA2AO2Q == ）。可悲的是，我不知道为什么结果不一样，因为我使用相同的算法和相同的密钥和iv。这是否意味着我的Java程序无法正常工作？任何帮助将不胜感激。

I get something diffrent than in Java program( Y65q9DFdR3k1XcWhA2AO2Q== ). Sadly I have no idea why results aren't the same since I use the same algorithm with the same key and iv. Does it mean my Java program doesn't work properly? Any help would be appreciated.

推荐答案

两种方式都正常工作，但是你正在加密不同的东西。

Both ways are working correctly, however you are encrypting different things.

此处的字符串语法（<<<< ）为字符串添加换行符。所以Java输出是加密a的结果，命令行输出是加密a \ n的结果（即字符 a 后跟一个换行符。

The here string syntax (<<<) adds a newline to the string. So the Java output is the result of encrypting "a", and the command line output is the result of encrypting "a\n" (i.e. the character a followed by a newline).

从命令行试试这个：

printf "a" | /usr/bin/openssl enc -aes-256-cbc -base64 -K "b38b730d4cc721156e3760d1d58546ce697adc939188e4c6a80f0e24e032b9b7" -iv "064df9633d9f5dd0b5614843f6b4b059"

结果是 VTUOJJp38Tk + P5ikR4YLfw == ，与您的Java结果相匹配。

the result is VTUOJJp38Tk+P5ikR4YLfw==, matching your Java result.

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