如何在角度和重复的同一请求中上传图像和数据？ [英] How can I upload image and data in the same request with angular and resteasy?

问题描述

我正面临一个问题，即在后端使用jax-rs制作角度问题。
crud非常简单，一些文本字段和一个图像字段。

I'm facing a problem to make a angular crud with jax-rs on backend. The crud is very simple, some text fields and a image field.

我有代码正在上传图片：

I have the code working to upload a image:

@POST
@Consumes("multipart/form-data")
public Response uploadFile(MultipartFormDataInput input) {
    ...
}

在html图层中：

<form action="http://localhost:8080/app/api/user" method="post" enctype="multipart/form-data">
   <p>
    Choose a file : <input type="file" name="file" />
   </p>
   <input type="submit" value="Upload" />
</form>

所以，我的问题是如何在这一步中这样做：

So, my question is how can I do this in one step like this:

@POST
@Consumes("multipart/form-data")
public Response save(MultipartFormDataInput input, MyEntity entity) {
    ...
}

如果我尝试调用上面的代码从视图层，wildfly给出一个错误，找不到要与MyEntity参数绑定的数据。

If I try to call the code above from view layer, the wildfly give a error that doesn't found data to bind with MyEntity parameter.

[org.jboss.resteasy.core.ExceptionHandler] (default task-3) failed to execute: javax.ws.rs.NotSupportedException: 
Could not find message body reader for type: class mypackage.MyEntity of content type: multipart/form-data;boundary=----WebKitFormBoundaryRXVvqLpZACPylNgS

有谁知道我该怎么做？或者我应该分两步完成它？

Does anyone knows how can I do that? Or shoud I do it in two steps?

推荐答案

从技术上讲，你可以从<$ c $获得两个数据C> MultipartFormDataInput 。例如

Technically, you can just get both pieces of data from the MultipartFormDataInput. For example

<form action="api/upload" method="post" enctype="multipart/form-data">
    Choose a file : <input type="file" name="file" />
    First name: <input type="text" name="firstname" />
    List name: <input type="text" name="lastname" />
    <input type="submit" value="Upload" />
</form>

@Consumes(MediaType.MULTIPART_FORM_DATA)
public Response upload(MultipartFormDataInput multipart) throws IOException {

    try (InputStream in = multipart.getFormDataPart("file", InputStream.class, null);
         FileOutputStream fos = new FileOutputStream("file.png")) {
        byte[] buff = new byte[1024];
        int count;
        while ((count = in.read(buff)) != -1) {
            fos.write(buff, 0, count);
        }
    }

    String firstname = multipart.getFormDataPart("firstname", String.class, null);
    String lastname = multipart.getFormDataPart("lastname", String.class, null);
    return Response.ok(firstname + ":" + lastname).build();
}

如果你想将所有东西放入POJO，你可以这样做

If you want to put everything into a POJO, you can do something like this

public class MyEntity {

    @FormParam("firstname")
    private String firstname;

    @FormParam("lastname")
    private String lastname;

    @FormParam("file")
    private byte[] file;

    // Getter and Setters
}

然后在你的资源方法

@Consumes(MediaType.MULTIPART_FORM_DATA)
public Response upload(@MultipartForm MyEntity entity) throws IOException {

    try (FileOutputStream fos = new FileOutputStream("file.png")) {
        byte[] filebytes = entity.getFile();
        fos.write(filebytes);
    }

    String firstname = entity.getFirstname();
    String lastname = entity.getLastname();
    return Response.ok(firstname + ":" + lastname).build();
}

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