URI.create（）vs new URI（） [英] URI.create() vs new URI()

问题描述

uri 可以通过两种方式创建：

  URI uri =新URI（https://www.google.com/）; 
  

或者，

  URI uri = URI.create（https://www.google.com/）; 
  

我想知道哪种方式更好。我没有注意到任何性能差异，我已经阅读了文档，但是有点难以理解。对此有任何见解表示赞赏。

解决方案

阅读文档时，它的用法不同。

通过解析给定的字符串来创建URI。这个便利工厂
方法就好像通过调用{@link
URI（String）}构造函数一样工作;构造函数抛出的任何{@link URISyntaxException}都被捕获并包装在一个新的{@link
IllegalArgumentException}对象中，然后抛出该对象。

此方法用于已知
给定字符串是合法URI 的情况，例如在程序中声明的URI常量
，因此它将是认为字符串不能解析为
编程错误。直接抛出{@link URISyntaxException}的
构造函数应该使用
来自用户输入构造URI或者来自可能容易出错的其他源的
。 / p>

@param str要解析为URI的字符串

  * @return新的URI 
 * 
 * @throws NullPointerException 
 *如果{@code str}是{@code null} 
 * 
 * @throws IllegalArgumentException 
 *如果给定的字符串违反了RFC& nbsp; 2396 
 * / 
  

  public static URI create（String str）{
 try {
 return new URI（str）; 
} catch（URISyntaxException x）{
抛出新的IllegalArgumentException（x.getMessage（），x）; 
} 
} 
  

A uri could be created in two ways:

URI uri = new URI("https://www.google.com/");

Or,

URI uri = URI.create("https://www.google.com/");

I was wondering which is a better practice. I haven't noticed any performance differences and I've read the documentation, however it was a bit difficult to understand. Any insight on this is appreciated.

解决方案

Reading the docs, it differs in the usage.

Creates a URI by parsing the given string.This convenience factory method works as if by invoking the {@link URI(String)} constructor; any {@link URISyntaxException} thrown by the constructor is caught and wrapped in a new {@link IllegalArgumentException} object, which is then thrown.

This method is provided for use in situations where it is known that the given string is a legal URI, for example for URI constants declared within in a program, and so it would be considered a programming error for the string not to parse as such. The constructors, which throw {@link URISyntaxException} directly, should be used situations where a URI is being constructed from user input or from some other source that may be prone to errors.

@param str The string to be parsed into a URI

 * @return The new URI
 *
 * @throws  NullPointerException
 *          If {@code str} is {@code null}
 *
 * @throws  IllegalArgumentException
 *          If the given string violates RFC 2396
 */

public static URI create(String str) {
    try {
        return new URI(str);
    } catch (URISyntaxException x) {
        throw new IllegalArgumentException(x.getMessage(), x);
    }
}

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