在Quartz中每50秒Cron表达一次 [英] Cron expression every 50 seconds in Quartz

问题描述

我使用Quartz运行我的作业，每隔50秒使用一个cron表达式：

I'm running my Jobs using Quartz with a cron expression every 50 seconds:

Cron_Expression = "0/50 * * * * ?"

我的工作在几秒钟内运行： 50,60,50,60 ，... 而不是每50秒！并且不会在第二个0运行。

What happens is that my job runs at the seconds: 50, 60, 50, 60,... and not every 50 seconds! and does not run at the second "0".

从0开始，每50秒正确的cron表达式是什么？

What is the right cron expression every 50 seconds starting at 0?

推荐答案

'/'语法指定期间的增量而不是重复间隔。不可否认，这是一个微妙而混乱的区别。

The '/' syntax specifies the increment during the period and not a repeat interval. Admittedly a subtle and confusing difference.

在这种情况下，1分钟内只有一个可用的增量（50秒）。第一个数字指定要开始的值，在这种情况下为0.在'/'之前指定'*'相当于指定0.因此作业将仅在分钟（0和60可互换）和50秒时触发。

In this case there is only one available increment (50 seconds) during the 1 minute period. The first number specifies the value to start with, in this case 0. Specifying '*' before the '/' is equivalent to specifying 0. So the job will only fire on the minute (0 and 60 are interchangeable) and at 50 seconds.

如果周期可以除以多个增量，例如0/10，那么每次都会触发每个周期，例如10,20,30等秒。

If the period can be divided by multiple increments, eg 0/10 then it will fire for each at each of those times, eg at 10, 20, 30 etc seconds.

如果你想让一个工作定期触发，那么你可以使用Quartz SimpleTrigger code> repeatInterval 指定。

If you want a job to trigger at a regular interval then you can use a Quartz SimpleTrigger with a repeatInterval specified.

这篇关于在Quartz中每50秒Cron表达一次的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！