通过二维数组迭代 [英] Iterate through 2 dimensional array

问题描述

我有一个连接四板，我用二维数组模拟（数组[x] [y] x = x坐标，y = y坐标）。我必须使用System.out.println，所以我必须遍历行。

I have a "connect four board" which I simulate with a 2d array (array[x][y] x=x coordinate, y = y coordinate). I have to use "System.out.println", so I have to iterate through the rows.

我需要一种迭代这种方式的方法[0,0] [ 1,0] [2,0] [3,0] [0,1] [1,1] [2,1]等

I need a way to iterate this way [0,0] [1,0] [2,0] [3,0] [0,1] [1,1] [2,1] etc

如果我使用正常过程：

for (int i = 0; i<array.length; i++){
     for (int j = 0; j<array[i].length; j++){
        string += array[i][j];
     } System.out.println(string)

}

它不起作用，因为它以这种方式迭代[0,0] [0,1] [0,2] [0,3]等

it doesnt work because it iterates this way [0,0] [0,1] [0,2] [0,3] etc

正常程序保持不变x并递增y直到列的结尾，但我需要在y中说并递增x直到行的结尾。

The normal procedure stays in x and increments y until the end of the column, but i need to say in y and increment x until the end of the row.

推荐答案

将它视为一个数组数组，这肯定会起作用。

Consider it as an array of arrays and this will work for sure.

int mat[][] = { {10, 20, 30, 40, 50, 60, 70, 80, 90},
                {15, 25, 35, 45},
                {27, 29, 37, 48},
                {32, 33, 39, 50, 51, 89},
              };


    for(int i=0; i<mat.length; i++) {
        for(int j=0; j<mat[i].length; j++) {
            System.out.println("Values at arr["+i+"]["+j+"] is "+mat[i][j]);
        }
    }

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