更改viewpager片段由buttonClick [英] Change viewpager fragment by a buttonClick
问题描述
我想通过点击一个按钮来改变viewpager片段。我有5片段,每个片段具有其自己的XML文件(frag1.xml,frag2.xml,等等)。每个片段都有它的5个按钮要转移到其他页面viewpager这一点。但问题是如何检查的FragmentPageAdapter哪个按钮被点击,以及如何到达那里?
I'm trying to change the viewpager fragment by clicking on a button. I have 5 fragments, each fragment has it's own xml file (frag1.xml, frag2.xml, and so on). Every fragment has it's 5 buttons that should go to other pages of the viewpager. But the problem is how do I check in the FragmentPageAdapter which button is clicked and how to get there?
我会表现出code我有那么它应该是清楚的,我想。你可以把它像一个主屏幕,有点的底部和我你点击一个特定的点,你会去到相应的屏幕。
I'll show the code I have then it should be clear I think. Think of it like a homescreen that has dots at the bottom and I you click a certain dot, you'll go to the corresponding screen.
FragmentPagerAdapter
public class MyFragmentPagerAdapter extends FragmentPagerAdapter{
final int PAGE_COUNT = 6;
/** Constructor of the class */
public MyFragmentPagerAdapter(FragmentManager fm) {
super(fm);
}
/** This method will be invoked when a page is requested to create */
@Override
public Fragment getItem(int arg0) {
switch(arg0){
case 0:
return new Fragment1();
case 1:
return new Fragment2();
case 2:
return new Fragment3();
case 3:
return new Fragment4();
case 4:
return new Fragment5();
default:
return null;
}
}
/** Returns the number of pages */
@Override
public int getCount() {
return PAGE_COUNT;
}
}
Frag1.java
public class Frag1 extends Fragment {
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
View v = inflater.inflate(R.layout.frag_one, container, false);
OnClickListener changeFrag = new OnClickListener() {
@Override
public void onClick(View v) {
/*When I click this button in my fragment, I'd like it to go to fragment 3 for example*/
}
};
ImageButton btnT = (ImageButton) v.findViewById(R.id.frag3);
btnT.setOnClickListener(changeFrag);
return v;
}
}
MainActivity
公共类MainActivity扩展FragmentActivity {
public class MainActivity extends FragmentActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);/** Getting a reference to the ViewPager defined the layout file */
ViewPager pager = (ViewPager) findViewById(R.id.pager);
/** Getting fragment manager */
FragmentManager fm = getSupportFragmentManager();
/** Instantiating FragmentPagerAdapter */
MyFragmentPagerAdapter pagerAdapter = new MyFragmentPagerAdapter(fm);
/** Setting the pagerAdapter to the pager object */
pager.setAdapter(pagerAdapter);
//pager.setPageTransformer(true, new ZoomOutPageTransformer());
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
getMenuInflater().inflate(R.menu.activity_main, menu);
return true;
}
}
是这样的可能吗?有人可以帮助我在正确的方向吗?
Is something like this possible? Can someone help me in the right direction please?
推荐答案
我不知道究竟你说的关于改变。
I'm not sure what exactly you said about "Change".
如果你问有关更改页面显示的索引,你可以尝试
If you're asking about change page display index, you can try
ViewPager.setCurrentItem(int pageIndex, boolean isSmoothScroll);
或者,如果你问变革的内容,这里就是我所做的。
Or, if you're asking about change content, here's what I did
public class MyPagerAdapter extends FragmentStatePagerAdapter
{
private FragmentManager fragMan;
private ArrayList<Fragment> fragments=new ArrayList<Fragment>();
public void clearAll() //You can clear any specified page if you want...
{
for(int i=0; i<fragments.size(); i++)
fragMan.beginTransaction().remove(fragments.get(i)).commit();
fragments.clear();
fragments=new ArrayList<Fragment>();
notifyDataSetChanged();
}
public void addList() //Add some new fragment...
{
listFrag=new ListFragment();
fragments.add(list);
}
}
希望它帮助〜
Hope it helps~
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